Chapter 3 ยท Trigonometric Functions

3.2 Trigonometric Functions of a Real Number

Wind a point round a circle of radius $1$: its coordinates after travelling a distance $x$ are $\cos x$ and $\sin x$. This one picture defines all six trigonometric functions for every real number, and explains their signs, ranges, periods and graphs.

In Class 10, $\sin A$ was "opposite over hypotenuse" in a right-angled triangle โ€” a definition that only works for $0^\circ\lt A\lt90^\circ$, because a right triangle cannot have an obtuse angle, let alone an angle of $-45^\circ$ or $750^\circ$. Yet the height of a seat on a Ferris wheel, the voltage of the mains supply and the position of a piston all depend on angles that keep growing. We need a definition of sine and cosine that works for every real number and agrees with the old one for acute angles.

The idea is beautifully simple: draw a circle of radius $1$ centred at the origin, start at the point $(1,0)$, and walk a distance $x$ round the circle. Wherever you stop, your $x$-coordinate is $\cos x$ and your $y$-coordinate is $\sin x$. In this section we make that precise, define the other four functions from sine and cosine, and work out their signs in each quadrant, their domains and ranges, and their graphs โ€” waves that repeat forever.

Sine and Cosine on the Unit Circle

๐Ÿ“˜ Definition 3.4 โ€” Sine and cosine of a real number

The unit circle is the circle $a^2+b^2=1$ of radius $1$ centred at the origin $O$. Let $x$ be any real number. Starting at $A(1,0)$, move along the unit circle a distance $|x|$ โ€” anticlockwise if $x\gt0$, clockwise if $x\lt0$ โ€” and let $P(a,b)$ be the point where you stop. Then

$$\cos x=a,\qquad \sin x=b .$$

Equivalently, by Definition 3.3, $\angle AOP$ is an angle of $x$ radians in standard position, and $P$ is the point where its terminal side meets the unit circle. So $\cos x$ and $\sin x$ are the coordinates of $P$: $\ P=(\cos x,\sin x)$.

Agreement with Class 10. If $0\lt x\lt\tfrac{\pi}{2}$, drop the perpendicular $PM$ to the $x$-axis. Triangle $OMP$ has a right angle at $M$, hypotenuse $OP=1$, and angle $x$ at $O$. Its Class 10 ratios are $\tfrac{OM}{OP}=a$ and $\tfrac{MP}{OP}=b$ โ€” exactly the new $\cos x$ and $\sin x$. So nothing you learnt is lost; the definition has simply been extended.

๐Ÿ“ Theorem 3.3 โ€” Basic properties of sine and cosine

For every real number $x$ and every integer $n$:

  1. $\sin^2x+\cos^2x=1$;
  2. $-1\le\sin x\le1$ and $-1\le\cos x\le1$;
  3. $\sin(x+2n\pi)=\sin x$ and $\cos(x+2n\pi)=\cos x$;
  4. $\sin(-x)=-\sin x$ and $\cos(-x)=\cos x$;
  5. $\sin x=0$ exactly when $x=n\pi$, and $\cos x=0$ exactly when $x=(2n+1)\tfrac{\pi}{2}$.

Proof. (1) $P(\cos x,\sin x)$ lies on $a^2+b^2=1$. (2) Then $\sin^2x=1-\cos^2x\le1$, so $|\sin x|\le1$; similarly for $\cos x$. (3) Adding $2n\pi$ adds $n$ complete laps of the circle (circumference $2\pi$), so we stop at the same $P$. (4) Walking the distance $|x|$ clockwise instead of anticlockwise lands at the mirror image of $P$ in the $x$-axis, $(a,-b)$. (5) $\sin x=0$ when $P$ is on the $x$-axis, i.e. at $(1,0)$ or $(-1,0)$, which we reach after $0,\pi,2\pi,\dots$ or $-\pi,-2\pi,\dots$ โ€” the multiples of $\pi$. $\cos x=0$ when $P$ is $(0,\pm1)$, reached at the odd multiples of $\tfrac{\pi}{2}$. $\blacksquare$

We write $\sin^2x$ for $(\sin x)^2$ โ€” not $\sin(x^2)$. Property (3) says that sine and cosine repeat every $2\pi$; property (4) says cosine is an even function and sine is an odd function. The quadrantal points give these values:

$x$$0$$\tfrac{\pi}{2}$$\pi$$\tfrac{3\pi}{2}$$2\pi$
$P$$(1,0)$$(0,1)$$(-1,0)$$(0,-1)$$(1,0)$
$\cos x$$1$$0$$-1$$0$$1$
$\sin x$$0$$1$$0$$-1$$0$
โœ๏ธ Example 1 โ€” Values from the unit circle
Find (a) $\sin\tfrac{3\pi}{2}$ and $\cos\tfrac{3\pi}{2}$ (b) $\cos5\pi$ (c) $\sin\left(-\tfrac{\pi}{2}\right)$ (d) $\sin\tfrac{13\pi}{6}$ (e) $\cos\left(-\tfrac{25\pi}{3}\right)$.
(a) Three quarters of the way round ($\tfrac34$ of $2\pi$), $P=(0,-1)$: $\sin\tfrac{3\pi}{2}=-1$, $\cos\tfrac{3\pi}{2}=0$.
(b), (c) $5\pi=4\pi+\pi$, so $\cos5\pi=\cos\pi=-1$. $\sin\left(-\tfrac{\pi}{2}\right)=-\sin\tfrac{\pi}{2}=-1$ (sine is odd) โ€” a quarter turn clockwise lands at $(0,-1)$.
(d) $\tfrac{13\pi}{6}=2\pi+\tfrac{\pi}{6}$, so $\sin\tfrac{13\pi}{6}=\sin\tfrac{\pi}{6}=\tfrac12$.
(e) Cosine is even: $\cos\left(-\tfrac{25\pi}{3}\right)=\cos\tfrac{25\pi}{3}$, and $\tfrac{25\pi}{3}=8\pi+\tfrac{\pi}{3}$. So the value is $\cos\tfrac{\pi}{3}=\tfrac12$.

The Six Functions and Their Signs

๐Ÿ“˜ Definition 3.5 โ€” Tangent, cotangent, secant and cosecant

For real $x$ and $n\in\mathbb{Z}$, wherever the denominator is not zero:

$$\tan x=\frac{\sin x}{\cos x}\ \ \left(x\ne(2n+1)\tfrac{\pi}{2}\right),\qquad \cot x=\frac{\cos x}{\sin x}\ \ (x\ne n\pi),$$ $$\sec x=\frac{1}{\cos x}\ \ \left(x\ne(2n+1)\tfrac{\pi}{2}\right),\qquad \operatorname{cosec}x=\frac{1}{\sin x}\ \ (x\ne n\pi).$$

These are the tangent, cotangent, secant and cosecant functions. Together with sine and cosine they are the six trigonometric functions.

๐Ÿ“ Theorem 3.4 โ€” The Pythagorean identities

For every real $x$ at which both sides are defined,

$$1+\tan^2x=\sec^2x\quad\left(x\ne(2n+1)\tfrac{\pi}{2}\right),\qquad 1+\cot^2x=\operatorname{cosec}^2x\quad(x\ne n\pi).$$

Proof. Divide $\sin^2x+\cos^2x=1$ by $\cos^2x$ (allowed, since $\cos x\ne0$): $\tan^2x+1=\sec^2x$. Divide instead by $\sin^2x\ne0$: $1+\cot^2x=\operatorname{cosec}^2x$. $\blacksquare$

The sign of each function depends only on the quadrant containing $P$. In Quadrant I both coordinates are positive, so all six functions are positive. In Quadrant II, $a\lt0$ and $b\gt0$: only $\sin$ (and its reciprocal $\operatorname{cosec}$) is positive. In Quadrant III both are negative, so their ratio $\tan$ (and $\cot$) is positive. In Quadrant IV only $\cos$ (and $\sec$) is positive.

๐Ÿงญ Problem-solving strategy โ€” The ASTC rule and finding the other five values

Signs. Going anticlockwise from Quadrant I: All, Sine, Tangent, Cosine are positive (memory aid: "Add Sugar To Coffee"). Reciprocals share signs: $\operatorname{cosec}$ with $\sin$, $\sec$ with $\cos$, $\cot$ with $\tan$.

  1. From the given value, use $\sin^2x+\cos^2x=1$, $1+\tan^2x=\sec^2x$ or $1+\cot^2x=\operatorname{cosec}^2x$ to find the size of a second function.
  2. Choose its sign from the quadrant (ASTC) โ€” this is the step students forget.
  3. Get the remaining functions as quotients and reciprocals, and check one of them with an identity.

The lab below also shows the reference angle โ€” the acute angle between the terminal side and the $x$-axis. By the symmetry of the circle the values at $\theta$ have the same size as at the reference angle; Section 3.3 proves this with the allied-angle formulae.

Interactive 1 โ€” The Unit Circle and the ASTC Rule

$P$ moves round the unit circle. The blue segment is $\cos\theta$ (the $x$-coordinate), the red segment is $\sin\theta$ (the $y$-coordinate), and the purple segment on the tangent line $x=1$ is $\tan\theta$. The shaded quadrant shows which functions are positive there. Watch $\tan\theta$ shoot off to infinity as $P$ approaches the top or bottom of the circle, where $\cos\theta=0$.

150ยฐ
$\theta$โ€”
$\cos\theta$โ€”
$\sin\theta$โ€”
$\tan\theta$โ€”
โœ๏ธ Example 2 โ€” Five values from one
If $\cos x=-\tfrac35$ and $x$ lies in the third quadrant, find the values of the other five trigonometric functions.
Size of sin $\sin^2x=1-\cos^2x=1-\tfrac{9}{25}=\tfrac{16}{25}$, so $\sin x=\pm\tfrac45$.
Sign In the third quadrant only $\tan$ and $\cot$ are positive, so $\sin x=-\tfrac45$.
The rest $\operatorname{cosec}x=-\tfrac54$, $\ \sec x=-\tfrac53$, $\ \tan x=\dfrac{-4/5}{-3/5}=\tfrac43$, $\ \cot x=\tfrac34$.
Check $1+\tan^2x=1+\tfrac{16}{9}=\tfrac{25}{9}=\sec^2x$ โœ“, and $\tan x\gt0$ in Quadrant III โœ“.
โœ๏ธ Example 3 โ€” Starting from the cotangent
If $\cot x=-\tfrac{5}{12}$ and $x$ lies in the second quadrant, find the values of the other five trigonometric functions.
Cosecant $\operatorname{cosec}^2x=1+\cot^2x=1+\tfrac{25}{144}=\tfrac{169}{144}$, so $\operatorname{cosec}x=\pm\tfrac{13}{12}$. In Quadrant II sine (hence cosecant) is positive: $\operatorname{cosec}x=\tfrac{13}{12}$, $\sin x=\tfrac{12}{13}$.
Cosine $\cos x=\cot x\cdot\sin x=-\tfrac{5}{12}\cdot\tfrac{12}{13}=-\tfrac{5}{13}$, so $\sec x=-\tfrac{13}{5}$.
Tangent $\tan x=\dfrac{1}{\cot x}=-\tfrac{12}{5}$.
Check $\sin^2x+\cos^2x=\tfrac{144}{169}+\tfrac{25}{169}=1$ โœ“.
โœ๏ธ Example 4 โ€” Large and negative angles
Find the values of (a) $\sin765^\circ$ (b) $\operatorname{cosec}(-1410^\circ)$ (c) $\tan\tfrac{19\pi}{3}$ (d) $\cot\left(-\tfrac{15\pi}{4}\right)$.
(a) $765^\circ=2\times360^\circ+45^\circ$, so $\sin765^\circ=\sin45^\circ=\tfrac{1}{\sqrt2}$.
(b) $-1410^\circ+4\times360^\circ=30^\circ$, so $\operatorname{cosec}(-1410^\circ)=\operatorname{cosec}30^\circ=2$.
(c) $\tfrac{19\pi}{3}=6\pi+\tfrac{\pi}{3}$, and $\tan$ repeats every $2\pi$ (it even repeats every $\pi$, Theorem 3.5 below): $\tan\tfrac{19\pi}{3}=\tan\tfrac{\pi}{3}=\sqrt3$.
(d) $-\tfrac{15\pi}{4}+4\pi=\tfrac{\pi}{4}$, so $\cot\left(-\tfrac{15\pi}{4}\right)=\cot\tfrac{\pi}{4}=1$.

Domain, Range, Period and Graphs

๐Ÿ“˜ Definition 3.6 โ€” Periodic function and period

A function $f$ is periodic if there is a positive number $T$ such that $f(x+T)=f(x)$ for every $x$ in its domain. The smallest such $T$ is the period of $f$. The graph of a periodic function is one piece, of width $T$, repeated forever to the left and to the right.

๐Ÿ“ Theorem 3.5 โ€” Periods of the trigonometric functions

$\sin$, $\cos$, $\sec$ and $\operatorname{cosec}$ have period $2\pi$; $\tan$ and $\cot$ have period $\pi$:

$$\tan(x+\pi)=\tan x,\qquad \cot(x+\pi)=\cot x .$$

Proof. By Theorem 3.3, $2\pi$ works for sine and cosine, hence for their reciprocals. No smaller positive $T$ works for sine: $\sin\left(\tfrac{\pi}{2}+T\right)=\sin\tfrac{\pi}{2}=1$ would need the point for $\tfrac{\pi}{2}+T$ to be $(0,1)$ again, which first happens after a full lap. For tangent: walking an extra distance $\pi$ (half a lap) takes $P(a,b)$ to the diametrically opposite point $(-a,-b)$, so $\tan(x+\pi)=\dfrac{-b}{-a}=\dfrac ba=\tan x$. Since $\tan x=0$ only at $x=n\pi$, no positive $T\lt\pi$ can work. $\blacksquare$

functiondomainrangeperiod
$\sin x$$\mathbb{R}$$[-1,1]$$2\pi$
$\cos x$$\mathbb{R}$$[-1,1]$$2\pi$
$\tan x$$\mathbb{R}-\left\{(2n+1)\tfrac{\pi}{2} : n\in\mathbb{Z}\right\}$$\mathbb{R}$$\pi$
$\cot x$$\mathbb{R}-\{n\pi : n\in\mathbb{Z}\}$$\mathbb{R}$$\pi$
$\sec x$$\mathbb{R}-\left\{(2n+1)\tfrac{\pi}{2} : n\in\mathbb{Z}\right\}$$(-\infty,-1]\cup[1,\infty)$$2\pi$
$\operatorname{cosec}x$$\mathbb{R}-\{n\pi : n\in\mathbb{Z}\}$$(-\infty,-1]\cup[1,\infty)$$2\pi$

The ranges of $\sec$ and $\operatorname{cosec}$ follow from $|\cos x|\le1$: the reciprocal of a number between $-1$ and $1$ (other than $0$) has size at least $1$. As $P$ moves round the circle, the values change like this:

Quadrant IQuadrant IIQuadrant IIIQuadrant IV
$\sin x$increases $0\to1$decreases $1\to0$decreases $0\to-1$increases $-1\to0$
$\cos x$decreases $1\to0$decreases $0\to-1$increases $-1\to0$increases $0\to1$
$\tan x$increases $0\to\infty$increases $-\infty\to0$increases $0\to\infty$increases $-\infty\to0$

Where $\cos x=0$, $\tan x$ and $\sec x$ are undefined and their graphs have vertical asymptotes โ€” lines the graph approaches but never meets. Likewise $\cot x$ and $\operatorname{cosec}x$ have asymptotes where $\sin x=0$.

Interactive 2 โ€” Graph Tracer: Period and Asymptotes

Choose a function. The shaded band is one period; the rest of the graph is copies of it. The tracer reads $f(x)$, and its twin one period further on (hollow dot) always has the same height. Dashed vertical lines are asymptotes, where the function is not defined.

$x$โ€”
$f(x)$โ€”
periodโ€”
rangeโ€”
โœ๏ธ Example 5 โ€” Ranges and periods
(a) Find the greatest and least values of $f(x)=2+3\cos x$ and the range of $f$.
(b) For which $x$ in $[0,2\pi]$ is $\tan x$ not defined?
(c) Show that $g(x)=\sin2x$ has period $\pi$.
(a) $-1\le\cos x\le1$, so $-3\le3\cos x\le3$ and $-1\le2+3\cos x\le5$. The greatest value $5$ occurs at $x=0$ ($\cos x=1$), the least value $-1$ at $x=\pi$; every value in between is taken because $\cos x$ takes every value in $[-1,1]$. Range $=[-1,5]$.
(b) $\tan x$ is undefined where $\cos x=0$: in $[0,2\pi]$ that is $x=\tfrac{\pi}{2}$ and $x=\tfrac{3\pi}{2}$.
(c) $g(x+\pi)=\sin(2x+2\pi)=\sin2x=g(x)$. And no smaller $T$ works: $g\left(\tfrac{\pi}{4}\right)=1$, and $\sin2x=1$ next happens when $2x=\tfrac{\pi}{2}+2\pi$, i.e. $x=\tfrac{\pi}{4}+\pi$. So the period is $\pi$ โ€” the graph of $\sin 2x$ is $\sin x$ squeezed to half its width.
โœ๏ธ Example 6 โ€” Signs at angles given in radians
Without a calculator, decide the sign of (a) $\sin4$ (b) $\cos(-3)$ (c) $\tan2$ (d) $\sec6$.
Landmarks $\tfrac{\pi}{2}\approx1.57$, $\pi\approx3.14$, $\tfrac{3\pi}{2}\approx4.71$, $2\pi\approx6.28$. Place each number between two landmarks to find its quadrant.
(a), (b) $\pi\lt4\lt\tfrac{3\pi}{2}$: Quadrant III, so $\sin4\lt0$. $\cos(-3)=\cos3$ and $\tfrac{\pi}{2}\lt3\lt\pi$: Quadrant II, so $\cos(-3)\lt0$.
(c), (d) $\tfrac{\pi}{2}\lt2\lt\pi$: Quadrant II, so $\tan2\lt0$. $\tfrac{3\pi}{2}\lt6\lt2\pi$: Quadrant IV, where cosine is positive, so $\sec6\gt0$.
Check A calculator in RAD mode gives $\sin4\approx-0.757$, $\cos3\approx-0.990$, $\tan2\approx-2.185$, $\sec6\approx1.041$ โœ“.
โš ๏ธ Common mistakes with trigonometric functions

1. $\sin^2x$ is not $\sin x^2$. $\sin^2x=(\sin x)^2$; $\sin x^2=\sin(x^2)$. And $\sin^{-1}x$ does not mean $\tfrac{1}{\sin x}$ โ€” write $\operatorname{cosec}x$ or $(\sin x)^{-1}$.

2. Forgetting the sign. $\sin^2x=\tfrac{16}{25}$ gives $\sin x=\pm\tfrac45$; only the quadrant decides which.

3. "$\sin x$" means $x$ in radians. $\sin2$ is the sine of $2$ radians ($\approx114.6^\circ$), a positive number about $0.909$ โ€” not $\sin2^\circ\approx0.035$.

4. Impossible values. $\sin x=1.2$ and $\sec x=0.5$ have no solutions; $\tan x$ and $\cot x$, on the other hand, take every real value.

5. The period of $\tan$ is $\pi$, not $2\pi$. $2\pi$ also "works", but the period is the smallest positive value that works.

Exercises

I
Values from the unit circle, periodicity and odd/even.
  • 1 $\sin\tfrac{3\pi}{2}+\cos\pi$
  • 2 $\cos 7\pi$
  • 3 $\sin\left(-\tfrac{7\pi}{2}\right)$
  • 4 $\sin405^\circ$
  • 5 $\cos(-1050^\circ)$
  • 6 $\tan\tfrac{13\pi}{4}$
  • 7 $\sec\tfrac{25\pi}{3}$
  • 8 $\operatorname{cosec}(-1110^\circ)$
  • 9 $\cos(-9\pi)$
  • 10 $\cot\tfrac{17\pi}{4}+\tan\left(-\tfrac{11\pi}{4}\right)$
1 $-1+(-1)=-2$.
2 $7\pi=6\pi+\pi$: $\cos7\pi=\cos\pi=-1$.
3 $-\tfrac{7\pi}{2}+4\pi=\tfrac{\pi}{2}$: the value is $\sin\tfrac{\pi}{2}=1$.
4 $405^\circ=360^\circ+45^\circ$: $\tfrac{1}{\sqrt2}$.
5 $-1050^\circ+3\times360^\circ=30^\circ$: $\cos30^\circ=\tfrac{\sqrt3}{2}$.
6 $\tfrac{13\pi}{4}=3\pi+\tfrac{\pi}{4}$ and $\tan$ has period $\pi$: $\tan\tfrac{\pi}{4}=1$.
7 $\tfrac{25\pi}{3}=8\pi+\tfrac{\pi}{3}$: $\sec\tfrac{\pi}{3}=2$.
8 $-1110^\circ+3\times360^\circ=-30^\circ$, and cosecant is odd: $\operatorname{cosec}(-30^\circ)=-\operatorname{cosec}30^\circ=-2$.
9 $\cos(-9\pi)=\cos9\pi=\cos(8\pi+\pi)=\cos\pi=-1$.
10 $\tfrac{17\pi}{4}=4\pi+\tfrac{\pi}{4}$, so $\cot\tfrac{17\pi}{4}=1$; $\tan$ has period $\pi$ and $-\tfrac{11\pi}{4}+3\pi=\tfrac{\pi}{4}$, so the second term is $\tan\tfrac{\pi}{4}=1$. Total $2$.
II
Signs, and the other five functions.
  • 1 Find the sign of $\sin200^\circ\cdot\cos300^\circ$.
  • 2 Find the sign of $\tan3$.
  • 3 Find the sign of $\cos5$.
  • 4 $\sin x=\tfrac35$, $x$ in Quadrant II. Find the other five values.
  • 5 $\tan x=-\tfrac{5}{12}$, $x$ in Quadrant IV. Find the other five values.
  • 6 $\sec x=\tfrac{13}{5}$, $x$ in Quadrant IV. Find the other five values.
  • 7 $\cot x=\tfrac34$, $x$ in Quadrant III. Find the other five values.
  • 8 $\sin x=-\tfrac12$ and $\tan x\gt0$. In which quadrant is $x$, and what is $\cos x$?
Check: all six values at any angle
143ยฐ
quadrantโ€”
$\sin,\ \operatorname{cosec}$โ€”
$\cos,\ \sec$โ€”
$\tan,\ \cot$โ€”
1 $200^\circ$ is in Quadrant III ($\sin\lt0$); $300^\circ$ in Quadrant IV ($\cos\gt0$). Product negative.
2 $\tfrac{\pi}{2}\lt3\lt\pi$: Quadrant II, $\tan3\lt0$.
3 $\tfrac{3\pi}{2}\approx4.71\lt5\lt2\pi$: Quadrant IV, $\cos5\gt0$.
4 $\cos x=-\tfrac45$, $\tan x=-\tfrac34$, $\cot x=-\tfrac43$, $\sec x=-\tfrac54$, $\operatorname{cosec}x=\tfrac53$.
5 $\sec^2x=1+\tfrac{25}{144}=\tfrac{169}{144}$, $\sec x=\tfrac{13}{12}$ (positive in IV); $\cos x=\tfrac{12}{13}$, $\sin x=\tan x\cos x=-\tfrac{5}{13}$, $\operatorname{cosec}x=-\tfrac{13}{5}$, $\cot x=-\tfrac{12}{5}$.
6 $\cos x=\tfrac{5}{13}$, $\sin x=-\tfrac{12}{13}$, $\tan x=-\tfrac{12}{5}$, $\cot x=-\tfrac{5}{12}$, $\operatorname{cosec}x=-\tfrac{13}{12}$.
7 $\operatorname{cosec}^2x=1+\tfrac{9}{16}=\tfrac{25}{16}$, $\operatorname{cosec}x=-\tfrac54$ (negative in III); $\sin x=-\tfrac45$, $\cos x=\cot x\sin x=-\tfrac35$, $\sec x=-\tfrac53$, $\tan x=\tfrac43$.
8 $\sin x\lt0$ and $\tan x\gt0$ only in Quadrant III. $\cos^2x=1-\tfrac14=\tfrac34$, so $\cos x=-\tfrac{\sqrt3}{2}$.
III
Identities, ranges and impossible values.
  • 1 Prove that $(1-\sin^2x)\sec^2x=1$, for $x\ne(2n+1)\tfrac{\pi}{2}$.
  • 2 Prove that $\sin^4x-\cos^4x=\sin^2x-\cos^2x$.
  • 3 Prove that $(\sec x-\tan x)(\sec x+\tan x)=1$, where defined.
  • 4 Prove that $\tan x+\cot x=\sec x\operatorname{cosec}x$, where defined.
  • 5 Find the range of $f(x)=5-2\sin x$.
  • 6 Find the greatest and least values of $3-4\cos x$, and where in $[0,2\pi]$ they occur.
  • 7 Which of these equations have solutions? (a) $\sin x=\tfrac43$ (b) $\sec x=\tfrac12$ (c) $\tan x=250$ (d) $\operatorname{cosec}x=-1$.
  • 8 Find all $x$ in $[0,2\pi]$ with $\cos x=0$, and all $x$ in $[0,2\pi]$ with $\sin x=0$.
1 $1-\sin^2x=\cos^2x$, and $\cos^2x\cdot\sec^2x=\cos^2x\cdot\dfrac{1}{\cos^2x}=1$.
2 $\sin^4x-\cos^4x=(\sin^2x-\cos^2x)(\sin^2x+\cos^2x)=(\sin^2x-\cos^2x)\cdot1$.
3 The product is $\sec^2x-\tan^2x=1$ by Theorem 3.4.
4 $\dfrac{\sin x}{\cos x}+\dfrac{\cos x}{\sin x}=\dfrac{\sin^2x+\cos^2x}{\sin x\cos x}=\dfrac{1}{\sin x\cos x}=\sec x\operatorname{cosec}x$.
5 $-1\le\sin x\le1$ gives $3\le5-2\sin x\le7$; range $[3,7]$.
6 Greatest $3+4=7$ when $\cos x=-1$ ($x=\pi$); least $3-4=-1$ when $\cos x=1$ ($x=0$ or $2\pi$).
7 (a) No: $|\sin x|\le1$. (b) No: $|\sec x|\ge1$. (c) Yes: $\tan$ takes every real value. (d) Yes: $x=\tfrac{3\pi}{2}$.
8 $\cos x=0$: $x=\tfrac{\pi}{2},\tfrac{3\pi}{2}$. $\sin x=0$: $x=0,\pi,2\pi$.
IV
Graphs, periods and models.
  • 1 State the period of $\cot x$, and the points of $(-\pi,\pi)$ where $\tan x$ is not defined.
  • 2 On which interval within $[0,2\pi]$ does $\cos x$ decrease, and on which does it increase?
  • 3 Show that $\cos3x$ is periodic with period $\tfrac{2\pi}{3}$ (you may assume no smaller period works).
  • 4 Giant wheel. The height of a cabin above the ground is $h(t)=20-18\cos\tfrac{\pi t}{5}$ metres, $t$ minutes after it passes the lowest point. Find $h(0)$, $h(5)$, the greatest and least heights, and the time for one revolution.
  • 5 Tides. The depth of water at a harbour entrance is $d(t)=6+2\sin\tfrac{\pi t}{6}$ metres, $t$ hours after midnight. Find the greatest and least depths, the first time each occurs, and the period.
  • 6 Sketch $y=\sin x$ and $y=\cos x$ on the same axes for $0\le x\le2\pi$, and find the values of $x$ where the graphs cross.
1 Period of $\cot x$: $\pi$. $\tan x$ is undefined at $x=-\tfrac{\pi}{2}$ and $x=\tfrac{\pi}{2}$.
2 Decreasing on $[0,\pi]$ (from $1$ to $-1$), increasing on $[\pi,2\pi]$ (from $-1$ back to $1$).
3 $\cos3\left(x+\tfrac{2\pi}{3}\right)=\cos(3x+2\pi)=\cos3x$ for every $x$.
4 $h(0)=20-18=2$ m; $h(5)=20-18\cos\pi=38$ m. Greatest $38$ m, least $2$ m. One revolution: $\tfrac{\pi t}{5}$ grows by $2\pi$ when $t$ grows by $10$ โ€” so $10$ minutes.
5 Greatest $8$ m when $\sin\tfrac{\pi t}{6}=1$, first at $\tfrac{\pi t}{6}=\tfrac{\pi}{2}$, $t=3$ (3 am). Least $4$ m first at $\tfrac{\pi t}{6}=\tfrac{3\pi}{2}$, $t=9$ (9 am). Period $12$ hours.
6 They cross where $\sin x=\cos x$, i.e. $\tan x=1$ (note $\cos x\ne0$ there). In $[0,2\pi]$: $x=\tfrac{\pi}{4}$ (Quadrant I, both $\tfrac1{\sqrt2}$) and $x=\tfrac{5\pi}{4}$ (Quadrant III, both $-\tfrac1{\sqrt2}$).
๐ŸŽฏ Exam corner Board ยท 1 markBoard ยท 2 marksBoard ยท 3 marksBoard ยท Case studyJEE MainJEE Advanced

How this is examined: the Board's favourite is "given one ratio and the quadrant, find the other five" (3 marks), plus values at large or negative angles (2 marks) and periodic models. JEE uses this section inside bigger problems: signs of $\sin2$ or $\tan4$, the range of an expression, or a value forced by $|\sin x|\le1$.

E1. Board ยท 1 mark If $\sin x=-\tfrac45$ and $x$ lies in the third quadrant, then $\tan x=$ (A) $\tfrac43$   (B) $-\tfrac43$   (C) $\tfrac34$   (D) $-\tfrac34$

Idea $\cos x=-\tfrac35$ (negative in Quadrant III), so $\tan x=\dfrac{-4/5}{-3/5}=\tfrac43$.
Trap (B) keeps the minus sign of $\sin x$ but forgets that $\cos x$ is negative too; in Quadrant III tangent is positive.
Answer (A) $\tfrac43$.

E2. Board ยท 2 marks Find the values of (i) $\sin(-1125^\circ)$ (ii) $\cot\tfrac{49\pi}{4}$.

(i) $\sin(-1125^\circ)=-\sin1125^\circ$, and $1125^\circ=3\times360^\circ+45^\circ$. So the value is $-\sin45^\circ=-\tfrac{1}{\sqrt2}$. (1 mark)
Answer (ii) $\tfrac{49\pi}{4}=12\pi+\tfrac{\pi}{4}$, so $\cot\tfrac{49\pi}{4}=\cot\tfrac{\pi}{4}=1$. (1 mark)

E3. Board ยท 3 marks If $\sec x=-\tfrac{13}{12}$ and $x$ lies in the third quadrant, find the values of the other five trigonometric functions.

Cosine and sine $\cos x=-\tfrac{12}{13}$. $\sin^2x=1-\tfrac{144}{169}=\tfrac{25}{169}$, and sine is negative in Quadrant III: $\sin x=-\tfrac{5}{13}$. (1 mark)
Tangent $\tan x=\dfrac{-5/13}{-12/13}=\tfrac{5}{12}$, $\cot x=\tfrac{12}{5}$. (1 mark)
Answer $\sin x=-\tfrac5{13}$, $\cos x=-\tfrac{12}{13}$, $\tan x=\tfrac5{12}$, $\cot x=\tfrac{12}5$, $\operatorname{cosec}x=-\tfrac{13}{5}$. (1 mark)

E4. Board ยท Case study A cabin on a giant wheel is $h(t)=22-20\cos\tfrac{\pi t}{10}$ metres above the ground, $t$ minutes after it passes the lowest point. (i) Find the least and greatest heights of the cabin. (2 marks) (ii) How long does one revolution take? (1 mark) (iii) Find the height after $5$ minutes. (1 mark)

(i) $-1\le\cos\tfrac{\pi t}{10}\le1$ gives $2\le h\le42$: least $2$ m (when $\cos=1$, e.g. $t=0$), greatest $42$ m (when $\cos=-1$, $t=10$). (2 marks)
(ii) The angle $\tfrac{\pi t}{10}$ increases by $2\pi$ when $t$ increases by $20$: one revolution takes $20$ minutes. (1 mark)
Answer (iii) $h(5)=22-20\cos\tfrac{\pi}{2}=22$ m โ€” a quarter turn, level with the hub. (1 mark)

E5. JEE Main If $\sin x+\operatorname{cosec}x=2$, then $\sin^{2026}x+\operatorname{cosec}^{2026}x$ equals (A) $2$   (B) $2^{2026}$   (C) $1$   (D) $0$

Idea Put $s=\sin x\ne0$: $s+\tfrac1s=2$ gives $s^2-2s+1=0$, $(s-1)^2=0$, so $s=1$ and $\operatorname{cosec}x=1$.
Trap (B) treats the sum as if it were $2$ raised to the power. Once $\sin x=1$, every power of it is $1$.
Answer (A) $1^{2026}+1^{2026}=2$. โฑ Fast route: for $t\gt0$, $t+\tfrac1t\ge2$ with equality only at $t=1$ (and $t\lt0$ makes the sum negative).

E6. JEE Advanced One or more options correct. Which of the following numbers are positive? (A) $\sin2$   (B) $\cos2$   (C) $\tan4$   (D) $\sec5$

(A), (B) $\tfrac{\pi}{2}\approx1.57\lt2\lt3.14$: Quadrant II, so $\sin2\gt0$ and $\cos2\lt0$.
(C) $3.14\lt4\lt4.71$: Quadrant III, where tangent is positive: $\tan4\gt0$.
(D) $4.71\lt5\lt6.28$: Quadrant IV, where cosine (so secant) is positive: $\sec5\gt0$.
Answer (A), (C), (D). The trap is reading the angles as degrees โ€” then all four would be positive.
๐Ÿ”ฌ Researchโ€“Teaching NexusMini project ยท about 1 hour

Research question. How well does a sine curve describe the length of the day in your town over a year?

Why it matters. Day length controls crop cycles, solar-panel output and energy demand. Climate scientists and power-grid planners model it โ€” and many other seasonal quantities โ€” with functions of the form $A+B\sin\tfrac{2\pi(t-c)}{365}$, because the Earth's orbit repeats every year.

What to do.

  1. From a weather app or almanac website, record the sunrise and sunset times in your town on the 1st and 15th of every month (24 values), and compute the day length in hours.
  2. Plot day length against day number $t$ ($1$ to $365$) in a spreadsheet.
  3. Estimate $A$ (the average day length), $B$ (half the difference between the longest and shortest days) and $c$ (the day on which the length is average and increasing, near 21 March).
  4. Plot $L(t)=A+B\sin\tfrac{2\pi(t-c)}{365}$ on the same axes and list the largest gap between model and data.
  5. Repeat with data for a city much farther from the equator (e.g. Oslo or Helsinki) and compare the values of $B$.

Tools: Weather or almanac website, spreadsheet with a chart

Hand in: Your data table, the graph with the fitted curve, the values of $A$, $B$, $c$, and three sentences on what the period and the amplitude mean physically.

Going further. Why is the period $365$ days and not $\tfrac{365}{2}$? What would the graph look like at the equator?

Instructor note: for Delhi, $A\approx12.1$ h and $B\approx1.8$ h; for Chennai $B$ is only about $1$ h, and for Oslo about $6$ h. At the equator $B\approx0$ โ€” the graph is nearly flat.

๐Ÿงช Self-check quiz

0/5 correct

Q1. $\cos(-\pi)$ equals

Q2. In which quadrant is $\sin x$ negative and $\cos x$ positive?

Q3. The period of $\tan x$ is

Q4. The range of $\sec x$ is

Q5. If $\tan x=\tfrac34$ and $x$ lies in the third quadrant, then $\cos x=$