Chapter 5 · Introduction

Chapter 5 — Magnetism and Matter

A bar magnet is a solenoid in disguise: its field is a dipole field, its field lines never end, and the way matter responds to a field — weakly against it, weakly with it, or overwhelmingly with it — sorts every material into one of three families.

For nearly a thousand years sailors crossed oceans by trusting a sliver of magnetised iron floating on water. Today a phone finds north with a magnetometer chip smaller than a grain of rice, an MRI scanner maps the water in your brain using a field tens of thousands of times stronger than the Earth's, and every electric car, wind turbine and hard-disk drive depends on permanent magnets made of carefully engineered alloys. Yet a magnet seems mysterious: nothing visible flows, and no battery is attached. Where does its field come from, and why does it pull on iron but not on aluminium?

Chapter 4 showed that electric currents produce magnetic fields and that a current loop behaves like a tiny magnet. This chapter turns the idea round. A bar magnet behaves exactly like a solenoid, because inside it countless atomic current loops are lined up; its far field has the same shape as the field of an electric dipole, and in a uniform field it turns and oscillates like a compass needle. Because there are no isolated magnetic poles, magnetic field lines always close on themselves — Gauss's law for magnetism. Then we look inside materials: the magnetisation they acquire in a field, the magnetic intensity that causes it, and the susceptibility that measures their response — weak and negative for diamagnets, weak and positive for paramagnets, and enormous for ferromagnets such as iron, which can even remember the field they were placed in.

Bar magnet & field lines→Equivalent solenoid→Dipole in a uniform field→Gauss's law for magnetism→M, H, χ and μr→Dia-, para- & ferromagnetism
🎯 By the end of this chapter you can…
  • describe the field of a bar magnet with field lines, explain why it behaves as an equivalent solenoid, and calculate its field on the axial and equatorial lines;
  • find the torque on and the potential energy of a magnetic dipole in a uniform field, and use $T=2\pi\sqrt{I/(mB)}$ for an oscillating needle;
  • use the analogy between electric and magnetic dipoles, and state and apply Gauss's law for magnetism;
  • use magnetisation, magnetic intensity, susceptibility and permeability, including $\mathbf B=\mu_0(\mathbf H+\mathbf M)$;
  • classify materials as diamagnetic, paramagnetic or ferromagnetic, explain ferromagnetism with domains, and apply Curie's law and the Curie temperature;
  • solve board, JEE Main, JEE Advanced and NEET problems on all of the above.
Teaser — Compass Needles round a Magnet

Each small needle turns its red north end along the local magnetic field, computed from the magnet's two poles. Drag the magnet to move it and watch every needle respond; press Play to rotate it. Then switch to a solenoid with the same magnetic moment — can you tell the two apart from the needles alone? Drag the large probe needle to read the field.

direction of $\mathbf m$—
probe distance $r$—
$B$ at probe (pole model)—
needle angle from $\mathbf m$—

Sections in this chapter

✅ Before you start
This chapter leans on Chapter 4 (Moving Charges and Magnetism): the magnetic field and the tesla, the field on the axis of a circular loop, the field inside a long solenoid ($B=\mu_0nI$), and the magnetic moment $m=NIA$ of a current loop and the torque on it. From electrostatics you need the electric dipole — its field on the axial and equatorial lines and the torque $\mathbf p\times\mathbf E$ in a uniform field (Section 1.2) — and electric flux and Gauss's law (Section 1.3), because most results here are their magnetic twins. Section 5.1 also uses rotational dynamics ($\tau=I\alpha$, Class 11 Physics, Chapter 6) and angular simple harmonic motion (Class 11 Physics, Chapter 13).