Chapter 2 · Acids, Bases and Salts

2.3 Salts and Their Everyday Uses

Table salt, baking soda, washing soda, bleaching powder and plaster of Paris are all salts that you meet every day. Learn how salts form from acids and bases, how to predict whether a salt solution is acidic, neutral or basic, and how common salt becomes the raw material for sodium hydroxide, chlorine and hydrogen.

Put a pinch of salt on your tongue and you taste the most familiar chemical in the world. Yet “salt” is a whole family. Bakers use baking soda to make idlis and cakes rise; washerwomen and factories use washing soda; swimming pools and drinking-water plants use bleaching powder; a doctor sets your broken arm in a cast of plaster of Paris. Each of these is a salt, and each comes from the same few ideas you already know: an acid and a base that cancel each other.

In this section you will see how salts are grouped into families, how to tell without any experiment whether a salt solution is acidic, neutral or basic, and how sea salt is turned — by passing electricity through its solution — into three valuable substances: sodium hydroxide, chlorine and hydrogen. Then you will meet the four everyday salts above, learn why some salts keep water inside their crystals, and see how plaster of Paris sets hard.

Salt Families and the pH of Salt Solutions

You met salts in Section 2.1 as the product of a neutralisation reaction. The name of every salt tells where it came from: the first word comes from the base, the second from the acid. Sodium chloride comes from sodium hydroxide and hydrochloric acid; potassium sulphate from potassium hydroxide and sulphuric acid.

📘 Definition 2.8 — Salt and salt family
A salt is an ionic compound formed when the hydrogen ions of an acid are replaced by a metal (or ammonium) ion — the product of the reaction of an acid with a base, besides water. Salts that have the same positive ion (such as $\mathrm{NaCl}$ and $\mathrm{Na_{2}SO_{4}}$) or the same negative ion (such as $\mathrm{NaCl}$ and $\mathrm{CaCl_{2}}$) belong to one family. Sodium chloride, sodium sulphate and sodium nitrate are the sodium salts; sodium chloride, potassium chloride and calcium chloride are the chlorides.

Writing the formula of a salt is a matter of making the charges balance (Section 3.2 shows why). The metal ion and the acid's negative ion are used in whatever numbers give a total charge of zero: $\mathrm{Na^{+}}$ with $\mathrm{SO_{4}^{2-}}$ needs two sodium ions, giving $\mathrm{Na_{2}SO_{4}}$; $\mathrm{Ca^{2+}}$ with $\mathrm{Cl^{-}}$ needs two chlorides, giving $\mathrm{CaCl_{2}}$. A salt such as $\mathrm{CuSO_{4}}$ is named after its parts: copper(II) sulphate.

Parent acidParent baseSalt (name)Solution of the salt
HCl (strong)NaOH (strong)$\mathrm{NaCl}$ (sodium chloride)neutral, pH $\approx 7$
$\mathrm{H_{2}SO_{4}}$ (strong)KOH (strong)$\mathrm{K_{2}SO_{4}}$ (potassium sulphate)neutral, pH $\approx 7$
HCl (strong)$\mathrm{NH_{4}OH}$ (weak)$\mathrm{NH_{4}Cl}$ (ammonium chloride)acidic, pH $\approx 5$
$\mathrm{H_{2}SO_{4}}$ (strong)$\mathrm{Cu(OH)_{2}}$ (weak)$\mathrm{CuSO_{4}}$ (copper(II) sulphate)acidic, pH $\approx 4$
$\mathrm{CH_{3}COOH}$ (weak)NaOH (strong)$\mathrm{CH_{3}COONa}$ (sodium ethanoate)basic, pH $\approx 9$
$\mathrm{H_{2}CO_{3}}$ (weak)NaOH (strong)$\mathrm{Na_{2}CO_{3}}$ (sodium carbonate)basic, pH $\approx 11$–$12$

The table shows a pattern. Salts are not all neutral: the pH of a salt solution depends on how strong the parent acid and base were (Section 2.2). The reason is simple. The ions of a strong parent hardly react with water and leave the pH alone. The ion of a weak parent holds on to the $\mathrm{H^{+}}$ or $\mathrm{OH^{-}}$ it came from, and takes some from water, so the solution turns basic or acidic. (The values in the table are typical for $0.1\ \mathrm{mol/L}$ solutions at room temperature.)

📐 Principle 2.8 — pH of a salt solution
Predict the pH of a dissolved salt from its parent acid and base:
  • strong acid + strong base $\rightarrow$ neutral salt, $\mathrm{pH}=7$ (e.g. $\mathrm{NaCl}$, $\mathrm{KNO_{3}}$, $\mathrm{Na_{2}SO_{4}}$);
  • strong acid + weak base $\rightarrow$ acidic salt, $\mathrm{pH}\lt 7$ (e.g. $\mathrm{NH_{4}Cl}$, $\mathrm{CuSO_{4}}$);
  • weak acid + strong base $\rightarrow$ basic salt, $\mathrm{pH}\gt 7$ (e.g. $\mathrm{Na_{2}CO_{3}}$, $\mathrm{CH_{3}COONa}$, $\mathrm{NaHCO_{3}}$).
(For a salt of a weak acid and a weak base, the result depends on which parent is relatively stronger; the rule does not decide it. The rule applies to salts that dissolve in water.)
✏️ Example 12 — Predicting the nature of salt solutions
Name the parent acid and base of each salt, say whether each is strong or weak, and predict the nature of its solution: (a) $\mathrm{KNO_{3}}$; (b) $\mathrm{NH_{4}Cl}$; (c) $\mathrm{Na_{2}CO_{3}}$; (d) $\mathrm{CuSO_{4}}$.
(a) $\mathrm{KNO_{3}}$: potassium hydroxide (strong) + nitric acid (strong) $\rightarrow$ neutral, pH 7.
(b) $\mathrm{NH_{4}Cl}$: ammonium hydroxide (weak) + hydrochloric acid (strong) $\rightarrow$ acidic, pH below 7.
(c) $\mathrm{Na_{2}CO_{3}}$: sodium hydroxide (strong) + carbonic acid (weak) $\rightarrow$ basic, pH above 7.
(d) $\mathrm{CuSO_{4}}$: copper(II) hydroxide (weak) + sulphuric acid (strong) $\rightarrow$ acidic; the solution turns blue litmus red (and is blue in colour).
✏️ Example 13 — From acid and base to salt
Write the balanced equations, with state symbols, for the formation of (a) potassium carbonate from potassium hydroxide and carbonic acid; (b) copper(II) sulphate from copper(II) hydroxide and sulphuric acid. Name the family each salt shares with sodium carbonate and sodium sulphate.
(a) The carbonate ion $\mathrm{CO_{3}^{2-}}$ needs two $\mathrm{K^{+}}$, so two KOH are used: $$\mathrm{2KOH(aq) + H_{2}CO_{3}(aq) \rightarrow K_{2}CO_{3}(aq) + 2H_{2}O(l)}$$ Check: K $2=2$; C $1=1$; O $2+3=3+2$; H $2+2=4=2\times2$. ✓
(b) $$\mathrm{Cu(OH)_{2}(s) + H_{2}SO_{4}(aq) \rightarrow CuSO_{4}(aq) + 2H_{2}O(l)}$$ Check: Cu $1=1$; S $1=1$; O $2+4=4+2$; H $2+2=4$. ✓
Families $\mathrm{K_{2}CO_{3}}$ is a carbonate (family of $\mathrm{Na_{2}CO_{3}}$); $\mathrm{CuSO_{4}}$ is a sulphate (family of $\mathrm{Na_{2}SO_{4}}$).
Interactive 1 — Salt-Family Builder

Choose a parent acid and a parent base, then press ▶ Play: the two solutions are poured together and the salt forms. First predict from the strengths — will the salt solution be acidic, neutral or basic? The flask turns the colour of universal indicator in the salt solution, and the equation is balanced for you.

salt formed—
parents—
solution is—
typical pH (0.1 mol/L)—
🚀 Beyond the board syllabus (JEE Main · NEET · JEE Advanced) — hydrolysis of salts

In JEE Main, NEET and JEE Advanced (as part of Class 11 ionic equilibrium); not in the Class 10 CBSE syllabus.

The change of pH in a salt solution is called hydrolysis. The ethanoate ion of a weak acid takes $\mathrm{H^{+}}$ from water: $\mathrm{CH_{3}COO^{-} + H_{2}O \rightleftharpoons CH_{3}COOH + OH^{-}}$, giving a basic solution; the ammonium ion gives some $\mathrm{H^{+}}$ to water: $\mathrm{NH_{4}^{+} + H_{2}O \rightleftharpoons NH_{3} + H_{3}O^{+}}$, giving an acidic solution. The ions $\mathrm{Na^{+}}$ and $\mathrm{Cl^{-}}$, of strong parents, do nothing — so $\mathrm{NaCl}$ is neutral. See Class 11 Chemistry, Ch. 6 — Equilibrium.

Common Salt and the Chlor-alkali Process

Common salt, sodium chloride $\mathrm{NaCl}$, is the salt in your kitchen. It is obtained from sea water, by letting the water evaporate in shallow pans in the sun, and from underground deposits of rock salt, which are mined like coal. Rock salt is often brown because of impurities; it is purified before it is eaten. Salt is essential for life, but it is also one of the most important raw materials of industry.

When electricity is passed through a concentrated solution of sodium chloride in water (called brine), a remarkable reaction takes place: the salt and water change into three new substances, and the solution becomes basic. Two of the products are gases, one at each electrode.

📘 Definition 2.9 — Chlor-alkali process
The chlor-alkali process is the electrolysis of brine. “Chlor” refers to chlorine and “alkali” to sodium hydroxide: $$\mathrm{2NaCl(aq) + 2H_{2}O(l) \rightarrow 2NaOH(aq) + Cl_{2}(g) + H_{2}(g)}$$ Chlorine gas $\mathrm{Cl_{2}}$ forms at the anode (positive electrode), hydrogen gas $\mathrm{H_{2}}$ forms at the cathode (negative electrode), and sodium hydroxide solution is left near the cathode. The products must be kept apart (a membrane separates the two halves of the cell); otherwise they react with each other.
📐 Principle 2.9 — What the chlor-alkali products are used for
  • Hydrogen $\mathrm{H_{2}}$: fuel, making margarine (hydrogenation of oils, Section 4.3) and ammonia for fertilisers. Burnt with chlorine, it gives hydrochloric acid: $\mathrm{H_{2}(g) + Cl_{2}(g) \rightarrow 2HCl(g)}$, used to clean steel and in medicines.
  • Chlorine $\mathrm{Cl_{2}}$: disinfecting drinking water and swimming pools; making PVC plastic, disinfectants and bleaching powder (below).
  • Sodium hydroxide $\mathrm{NaOH}$ (caustic soda): degreasing metals; making soaps and detergents, paper and artificial fibres. With chlorine it gives household bleach: $\mathrm{Cl_{2} + 2NaOH \rightarrow NaOCl + NaCl + H_{2}O}$.

Notice how the equation balances: the left side has two $\mathrm{Na}$, two $\mathrm{Cl}$, four $\mathrm{H}$ and two $\mathrm{O}$, and so does the right side. The mass balances too: $117\ \mathrm{g}$ of $\mathrm{NaCl}$ and $36\ \mathrm{g}$ of water ($153\ \mathrm{g}$) give $80\ \mathrm{g}$ of $\mathrm{NaOH}$, $71\ \mathrm{g}$ of $\mathrm{Cl_{2}}$ and $2\ \mathrm{g}$ of $\mathrm{H_{2}}$ ($153\ \mathrm{g}$).

✏️ Example 14 — How much from a pinch of brine?
A brine solution containing $5.85\ \mathrm{g}$ of sodium chloride is completely electrolysed. With $\mathrm{Na}=23$, $\mathrm{Cl}=35.5$, $\mathrm{O}=16$, $\mathrm{H}=1\ \mathrm{u}$, find the masses of (a) sodium hydroxide, (b) chlorine and (c) hydrogen formed. (d) What mass of water is used up, and is mass conserved?
Step 1 $2\,\mathrm{NaCl}=2\times58.5=117\ \mathrm{u}$. The mass of $\mathrm{NaCl}$ is $\tfrac{5.85}{117}=0.05$ of this, so every product mass is $0.05$ of its equation mass.
(a) $2\,\mathrm{NaOH}=80\ \mathrm{u}$: $0.05\times80=4.00\ \mathrm{g}$.
(b) $\mathrm{Cl_{2}}=71\ \mathrm{u}$: $0.05\times71=3.55\ \mathrm{g}$. (c) $\mathrm{H_{2}}=2\ \mathrm{u}$: $0.05\times2=0.10\ \mathrm{g}$.
(d) Water: $2\,\mathrm{H_{2}O}=36\ \mathrm{u}$, so $0.05\times36=1.80\ \mathrm{g}$. Check: $5.85+1.80=7.65\ \mathrm{g}$ before; $4.00+3.55+0.10=7.65\ \mathrm{g}$ after. ✓
Interactive 2 — Chlor-alkali Cell

Press ▶ Play to pass electricity through brine. Chlorine bubbles off at the anode, hydrogen at the cathode, and the cathode side turns blue-violet as sodium hydroxide builds up. Choose a test for each gas. Predict the ratio of the two gas volumes first.

H₂ at cathode—
Cl₂ at anode—
NaOH formed—
NaCl used—

Baking Soda and Washing Soda

Baking soda, sodium hydrogencarbonate $\mathrm{NaHCO_{3}}$, is made from brine (common salt solution), ammonia and carbon dioxide: $$\mathrm{NaCl(aq) + H_{2}O(l) + CO_{2}(g) + NH_{3}(g) \rightarrow NH_{4}Cl(aq) + NaHCO_{3}(s)}$$ It is a mild, non-corrosive base: its solution has pH about 8.3 (Principle 2.8: weak acid, strong base). It is used in cooking, in antacids (Section 2.2), in soda-acid fire extinguishers and in cleaning.

📐 Principle 2.10 — Reactions and uses of baking soda
  • With an acid: $\mathrm{NaHCO_{3} + H^{+}}$ gives carbon dioxide: $\mathrm{NaHCO_{3}(s) + HCl(aq) \rightarrow NaCl(aq) + H_{2}O(l) + CO_{2}(g)}$.
  • On heating it decomposes: $\mathrm{2NaHCO_{3}(s) \xrightarrow{\text{heat}} Na_{2}CO_{3}(s) + H_{2}O(l) + CO_{2}(g)}$.
  • Baking powder is a mixture of baking soda and a mild solid acid such as tartaric acid. Water starts a reaction between them, and the carbon dioxide formed makes bread and cakes rise, soft and spongy. (Baking soda alone would leave bitter sodium carbonate in the cake.)
  • Soda-acid fire extinguisher: sulphuric acid mixes with baking soda solution: $\mathrm{H_{2}SO_{4}(aq) + 2NaHCO_{3}(aq) \rightarrow Na_{2}SO_{4}(aq) + 2H_{2}O(l) + 2CO_{2}(g)}$. The carbon dioxide smothers the fire.

Washing soda comes from baking soda. Heating baking soda gives sodium carbonate $\mathrm{Na_{2}CO_{3}}$ (soda ash), a white powder. Dissolve it in water and let it crystallise, and it takes ten molecules of water into each crystal: $$\mathrm{Na_{2}CO_{3}(s) + 10H_{2}O(l) \rightarrow Na_{2}CO_{3}\cdot 10H_{2}O(s)}$$ This second, hydrated salt is washing soda. Recovering a salt as purer crystals from its solution in this way is called recrystallisation.

📐 Principle 2.11 — Washing soda
Washing soda is a transparent crystalline salt, $\mathrm{Na_{2}CO_{3}\cdot 10H_{2}O}$. Its solution is basic (pH about 11) because $\mathrm{H_{2}CO_{3}}$ is a weak acid and $\mathrm{NaOH}$ a strong base. Uses: in glass, soap and paper industries; in making borax; in household cleaning of grease and clothes; and for removing permanent hardness of water.
✏️ Example 15 — Heating baking soda
A student heats $8.4\ \mathrm{g}$ of sodium hydrogencarbonate until no more gas is given off. (a) Write the balanced equation and name the gas, with a test. (b) With $\mathrm{Na}=23$, $\mathrm{H}=1$, $\mathrm{C}=12$, $\mathrm{O}=16\ \mathrm{u}$, find the masses of sodium carbonate, carbon dioxide and water formed. (c) Is mass conserved?
(a) $$\mathrm{2NaHCO_{3}(s) \rightarrow Na_{2}CO_{3}(s) + H_{2}O(l) + CO_{2}(g)}$$ The gas is carbon dioxide; it turns lime water milky. Check: Na $2=2$; H $2=2$; C $2=1+1$; O $6=3+1+2$. ✓
Ratio $2\,\mathrm{NaHCO_{3}}=168\ \mathrm{u}$; $\mathrm{Na_{2}CO_{3}}=106\ \mathrm{u}$; $\mathrm{CO_{2}}=44\ \mathrm{u}$; $\mathrm{H_{2}O}=18\ \mathrm{u}$. The mass taken is $\tfrac{8.4}{168}=0.05$ of the equation masses.
(b) $\mathrm{Na_{2}CO_{3}}$: $0.05\times106=5.3\ \mathrm{g}$; $\mathrm{CO_{2}}$: $0.05\times44=2.2\ \mathrm{g}$; $\mathrm{H_{2}O}$: $0.05\times18=0.9\ \mathrm{g}$.
(c) $5.3+2.2+0.9=8.4\ \mathrm{g}$, the mass we started with. ✓

Bleaching Powder, Water of Crystallisation and Plaster of Paris

Bleaching powder is made by passing the chlorine from the chlor-alkali cell over dry slaked lime: $$\mathrm{Cl_{2}(g) + Ca(OH)_{2}(s) \rightarrow CaOCl_{2}(s) + H_{2}O(l)}$$ Its chemical name is calcium oxychloride, with the formula $\mathrm{CaOCl_{2}}$ (often written $\mathrm{Ca(OCl)Cl}$).

📐 Principle 2.12 — Bleaching powder
Bleaching powder $\mathrm{CaOCl_{2}}$ is a pale-yellow powder with a smell of chlorine. It releases chlorine, which makes it useful for: bleaching cotton and linen in the textile industry, wood pulp in paper factories and clothes in laundries; as an oxidising agent in industry; and for disinfecting drinking water and swimming pools.

Now look at a different kind of salt. Heat a few blue crystals of copper sulphate in a dry boiling tube. The crystals lose their colour and turn white, and drops of water collect on the cool upper part of the tube. Add two or three drops of water to the white powder, and the blue colour returns. The blue crystals therefore contain water, which is part of the crystal, even though the crystals feel dry.

📘 Definition 2.10 — Water of crystallisation
Water of crystallisation is the fixed number of water molecules that are part of one formula unit of a salt. A salt that has it is a hydrated salt; without it, it is anhydrous. Examples: $\mathrm{CuSO_{4}\cdot 5H_{2}O}$ (blue crystals); $\mathrm{Na_{2}CO_{3}\cdot 10H_{2}O}$ (washing soda); $\mathrm{CaSO_{4}\cdot 2H_{2}O}$ (gypsum). Heating drives the water out: $$\mathrm{CuSO_{4}\cdot 5H_{2}O(s) \xrightarrow{\text{heat}} CuSO_{4}(s) + 5H_{2}O(g)}$$

Do not confuse crystal water with dampness. Copper sulphate crystals contain exactly five water molecules for each $\mathrm{CuSO_{4}}$, and they stay blue and dry-looking until you heat them. Pure common salt crystals contain no water of crystallisation at all.

Plaster of Paris is a hydrated salt with only half a molecule of water. It is made by heating gypsum, $\mathrm{CaSO_{4}\cdot 2H_{2}O}$, at $373\ \mathrm{K}$ ($100\ ^{\circ}\mathrm{C}$): $$\mathrm{CaSO_{4}\cdot 2H_{2}O(s) \xrightarrow{373\ \mathrm{K}} CaSO_{4}\cdot\tfrac{1}{2}H_{2}O(s) + 1\tfrac{1}{2}H_{2}O(g)}$$ (Doubling to avoid fractions: $\mathrm{2CaSO_{4}\cdot 2H_{2}O \rightarrow (CaSO_{4})_{2}\cdot H_{2}O + 3H_{2}O}$.) It is a white powder. Mix it with water and it sets, within minutes, into a hard solid mass of gypsum: $$\mathrm{CaSO_{4}\cdot\tfrac{1}{2}H_{2}O(s) + 1\tfrac{1}{2}H_{2}O(l) \rightarrow CaSO_{4}\cdot 2H_{2}O(s)}$$

📐 Principle 2.13 — Plaster of Paris
Plaster of Paris $\mathrm{CaSO_{4}\cdot\tfrac{1}{2}H_{2}O}$ sets into hard gypsum when mixed with water. It is used to make plaster casts for supporting fractured bones, toys and decorative objects, and to smooth walls and ceilings before painting. It must be kept in a moisture-proof container, since damp air would set it. Gypsum must not be heated much above $373\ \mathrm{K}$: more water is lost, and the product no longer sets well.
✏️ Example 16 — Water in the crystals
With $\mathrm{Cu}=63.5$, $\mathrm{S}=32$, $\mathrm{O}=16$, $\mathrm{H}=1\ \mathrm{u}$: (a) find the percentage by mass of water in $\mathrm{CuSO_{4}\cdot 5H_{2}O}$; (b) find the mass of white anhydrous $\mathrm{CuSO_{4}}$ and of water obtained on heating $24.95\ \mathrm{g}$ of the blue crystals completely; (c) What do you see when water is added to the white solid?
(a) $\mathrm{CuSO_{4}}=63.5+32+64=159.5\ \mathrm{u}$; $5\mathrm{H_{2}O}=90\ \mathrm{u}$; total $249.5\ \mathrm{u}$. Percentage of water $=\tfrac{90}{249.5}\times100=36.1\,\%$ (to 3 s.f.).
(b) $24.95\ \mathrm{g}$ is $\tfrac{24.95}{249.5}=0.1$ of the formula mass. Anhydrous $\mathrm{CuSO_{4}}$: $0.1\times159.5=15.95\ \mathrm{g}$. Water: $0.1\times90=9.0\ \mathrm{g}$. Check: $15.95+9.0=24.95\ \mathrm{g}$. ✓
(c) The white powder turns blue again as the crystals re-form with water of crystallisation (and warms slightly). This is used as a test for water.
✏️ Example 17 — Plaster of Paris and bleaching powder
(a) How much plaster of Paris is obtained from $3.44\ \mathrm{kg}$ of gypsum, and how much water is lost? ($\mathrm{Ca}=40$, $\mathrm{S}=32$, $\mathrm{O}=16$, $\mathrm{H}=1\ \mathrm{u}$.) (b) What mass of bleaching powder is made when $7.1\ \mathrm{g}$ of chlorine reacts with enough slaked lime? ($\mathrm{Cl}=35.5$.) (c) A doctor mixes plaster of Paris with water to cast a broken arm. Name the compound that forms.
(a) $\mathrm{CaSO_{4}}=136\ \mathrm{u}$, so gypsum $=136+36=172\ \mathrm{u}$ and plaster of Paris $\mathrm{CaSO_{4}\cdot\tfrac{1}{2}H_{2}O}=136+9=145\ \mathrm{u}$. Mass of plaster of Paris $=3.44\times\tfrac{145}{172}=2.90\ \mathrm{kg}$; water lost $=3.44-2.90=0.54\ \mathrm{kg}$ (that is $3.44\times\tfrac{27}{172}$). ✓
(b) $\mathrm{Cl_{2}}=71\ \mathrm{u}$ gives $\mathrm{CaOCl_{2}}=40+16+71=127\ \mathrm{u}$. Mass of bleaching powder $=7.1\times\tfrac{127}{71}=12.7\ \mathrm{g}$. (The slaked lime used is $7.4\ \mathrm{g}$, and $1.8\ \mathrm{g}$ of water is formed: $7.1+7.4=12.7+1.8=14.5\ \mathrm{g}$. ✓)
(c) Gypsum, $\mathrm{CaSO_{4}\cdot 2H_{2}O}$, which is hard and keeps the bone still.
⚠️ Common mistakes with everyday salts

1. “All salts are neutral.” Only salts of a strong acid with a strong base are. $\mathrm{Na_{2}CO_{3}}$ is basic and $\mathrm{NH_{4}Cl}$ is acidic.

2. Confusing baking soda and washing soda. Baking soda is $\mathrm{NaHCO_{3}}$ (one $\mathrm{H}$ still present, no water of crystallisation); washing soda is $\mathrm{Na_{2}CO_{3}\cdot 10H_{2}O}$.

3. Writing plaster of Paris with the wrong water. It is $\mathrm{CaSO_{4}\cdot\tfrac{1}{2}H_{2}O}$; gypsum is $\mathrm{CaSO_{4}\cdot 2H_{2}O}$.

4. Mixing up the electrodes in chlor-alkali. Chlorine is at the anode, hydrogen at the cathode, and sodium hydroxide stays in solution.

5. Calling water of crystallisation “wetness”. It is a fixed number of water molecules built into the crystal.

Exercises

I
Salts, families and their pH.
  • 1 What is a salt? Give three examples.
  • 2 Name the parent acid and parent base of (a) $\mathrm{NaCl}$, (b) $\mathrm{K_{2}SO_{4}}$, (c) $\mathrm{NH_{4}Cl}$, (d) $\mathrm{Ca(NO_{3})_{2}}$.
  • 3 Sort $\mathrm{NaCl}$, $\mathrm{Na_{2}SO_{4}}$, $\mathrm{KCl}$, $\mathrm{K_{2}SO_{4}}$ into families by their positive ion and by their negative ion.
  • 4 Predict whether the solution of each is acidic, neutral or basic: $\mathrm{KNO_{3}}$, $\mathrm{NH_{4}Cl}$, $\mathrm{CH_{3}COONa}$.
  • 5 A salt solution turns red litmus blue. What kind of acid and base formed it?
  • 6 Write balanced equations, with state symbols, for (a) sodium hydroxide + nitric acid; (b) copper(II) hydroxide + sulphuric acid; (c) potassium hydroxide + carbonic acid.
  • 7 Sodium chloride solution is neutral but sodium carbonate solution is basic. Explain using the parent acids and bases.
  • 8 What is the nature of copper(II) sulphate solution? Why?
1 An ionic compound formed when an acid and a base neutralise each other (besides water), e.g. $\mathrm{NaCl}$, $\mathrm{K_{2}SO_{4}}$, $\mathrm{CuSO_{4}}$.
2 (a) HCl and NaOH; (b) $\mathrm{H_{2}SO_{4}}$ and KOH; (c) HCl and $\mathrm{NH_{4}OH}$; (d) $\mathrm{HNO_{3}}$ and $\mathrm{Ca(OH)_{2}}$.
3 Sodium salts: NaCl, $\mathrm{Na_{2}SO_{4}}$. Potassium salts: KCl, $\mathrm{K_{2}SO_{4}}$. Chlorides: NaCl, KCl. Sulphates: $\mathrm{Na_{2}SO_{4}}$, $\mathrm{K_{2}SO_{4}}$.
4 $\mathrm{KNO_{3}}$ (strong + strong): neutral; $\mathrm{NH_{4}Cl}$ (strong acid + weak base): acidic; $\mathrm{CH_{3}COONa}$ (weak acid + strong base): basic.
5 The solution is basic, so the salt is from a weak acid and a strong base (like $\mathrm{Na_{2}CO_{3}}$).
6 (a) $\mathrm{NaOH(aq) + HNO_{3}(aq) \rightarrow NaNO_{3}(aq) + H_{2}O(l)}$; (b) $\mathrm{Cu(OH)_{2}(s) + H_{2}SO_{4}(aq) \rightarrow CuSO_{4}(aq) + 2H_{2}O(l)}$; (c) $$\mathrm{2KOH(aq) + H_{2}CO_{3}(aq) \rightarrow K_{2}CO_{3}(aq) + 2H_{2}O(l)}$$
7 NaCl comes from a strong acid (HCl) and a strong base (NaOH), so it is neutral. $\mathrm{Na_{2}CO_{3}}$ comes from the weak acid $\mathrm{H_{2}CO_{3}}$ and strong base NaOH, so the solution is basic.
8 Acidic (pH about 4): the parents are a strong acid, $\mathrm{H_{2}SO_{4}}$, and a weak base, $\mathrm{Cu(OH)_{2}}$.
II
Common salt and the chlor-alkali process.
  • 1 Name two sources of common salt. Why are crystals of rock salt often brown?
  • 2 Write the balanced equation for the electrolysis of brine. At which electrode does each gas form?
  • 3 Give two uses each of hydrogen, chlorine and sodium hydroxide from this process.
  • 4 What is formed when hydrogen burns in chlorine? Write the equation.
  • 5 A solution containing $11.7\ \mathrm{g}$ of $\mathrm{NaCl}$ is completely electrolysed. With $\mathrm{Na}=23$, $\mathrm{Cl}=35.5$, $\mathrm{H}=1$, $\mathrm{O}=16\ \mathrm{u}$ find the masses of $\mathrm{NaOH}$, $\mathrm{Cl_{2}}$, $\mathrm{H_{2}}$ formed and of water used.
  • 6 Why must chlorine and sodium hydroxide be kept apart in the cell? Write the equation of their reaction.
  • 7 Phenolphthalein is added near the cathode during the electrolysis. What colour appears, and why?
  • 8 Write the equation for making bleaching powder from chlorine.
1 Sea water (evaporated) and rock salt deposits. Rock salt is brown because of impurities.
2 $$\mathrm{2NaCl(aq) + 2H_{2}O(l) \rightarrow 2NaOH(aq) + Cl_{2}(g) + H_{2}(g)}$$ Chlorine at the anode (+); hydrogen at the cathode (−).
3 Hydrogen: fuel, margarine, ammonia. Chlorine: water treatment, PVC, disinfectants. NaOH: soaps and detergents, paper, degreasing metals (any two each).
4 Hydrogen chloride, which dissolves in water to give hydrochloric acid: $\mathrm{H_{2}(g) + Cl_{2}(g) \rightarrow 2HCl(g)}$.
5 $11.7\ \mathrm{g}$ is $\tfrac{11.7}{117}=0.1$ of the equation mass. $\mathrm{NaOH}$: $0.1\times80=8.0\ \mathrm{g}$; $\mathrm{Cl_{2}}$: $0.1\times71=7.1\ \mathrm{g}$; $\mathrm{H_{2}}$: $0.1\times2=0.20\ \mathrm{g}$; water: $0.1\times36=3.6\ \mathrm{g}$. Check: $11.7+3.6=15.3=8.0+7.1+0.2$. ✓
6 They would react: $\mathrm{Cl_{2}(g) + 2NaOH(aq) \rightarrow NaOCl(aq) + NaCl(aq) + H_{2}O(l)}$, using up the products (and the hydrogen and chlorine could form an explosive mixture).
7 Pink: the solution near the cathode contains sodium hydroxide, a base.
8 $\mathrm{Cl_{2}(g) + Ca(OH)_{2}(s) \rightarrow CaOCl_{2}(s) + H_{2}O(l)}$.
III
Baking soda and washing soda.
  • 1 Give the chemical name and formula of baking soda, and write the equation of its preparation from brine.
  • 2 What happens when baking soda is heated? Write the balanced equation and a test for the gas.
  • 3 Why do bakers use baking powder rather than baking soda alone?
  • 4 State three uses of baking soda.
  • 5 Give the formula of washing soda and show how it is obtained from baking soda.
  • 6 State three uses of washing soda. Is its solution acidic or basic? Why?
  • 7 Write the equation of the reaction in a soda-acid fire extinguisher. How does the product put out the fire?
  • 8 What mass of sodium carbonate and of carbon dioxide forms on heating $16.8\ \mathrm{g}$ of $\mathrm{NaHCO_{3}}$?
  • 9 Applied. $28.6\ \mathrm{g}$ of washing soda crystals are heated until dry. What masses of anhydrous sodium carbonate and of water are obtained? ($\mathrm{Na_{2}CO_{3}\cdot 10H_{2}O}=286\ \mathrm{u}$, $\mathrm{Na_{2}CO_{3}}=106\ \mathrm{u}$.)
1 Sodium hydrogencarbonate, $\mathrm{NaHCO_{3}}$: $\mathrm{NaCl + H_{2}O + CO_{2} + NH_{3} \rightarrow NH_{4}Cl + NaHCO_{3}}$.
2 It decomposes to sodium carbonate, water and carbon dioxide: $\mathrm{2NaHCO_{3}(s) \rightarrow Na_{2}CO_{3}(s) + H_{2}O(l) + CO_{2}(g)}$. The gas turns lime water milky.
3 Baking powder also contains a solid acid (tartaric acid), which reacts with the soda and releases $\mathrm{CO_{2}}$ to make the cake rise. Baking soda alone leaves bitter sodium carbonate in the cake.
4 Baking powder, antacid, soda-acid fire extinguishers, and cleaning (any three).
5 $\mathrm{Na_{2}CO_{3}\cdot 10H_{2}O}$. Heat baking soda to get $\mathrm{Na_{2}CO_{3}}$, dissolve it in water and recrystallise: $\mathrm{Na_{2}CO_{3} + 10H_{2}O \rightarrow Na_{2}CO_{3}\cdot 10H_{2}O}$.
6 Glass, soap and paper industries, removing hardness of water, cleaning (any three). Basic: weak acid ($\mathrm{H_{2}CO_{3}}$) and strong base (NaOH).
7 $$\mathrm{H_{2}SO_{4}(aq) + 2NaHCO_{3}(aq) \rightarrow Na_{2}SO_{4}(aq) + 2H_{2}O(l) + 2CO_{2}(g)}$$ Carbon dioxide neither burns nor supports burning and blankets the fire.
8 $16.8\ \mathrm{g}$ is $\tfrac{16.8}{168}=0.1$ of the equation mass: $\mathrm{Na_{2}CO_{3}}$ $0.1\times106=10.6\ \mathrm{g}$; $\mathrm{CO_{2}}$ $0.1\times44=4.4\ \mathrm{g}$ (and $1.8\ \mathrm{g}$ of water).
9 $28.6\ \mathrm{g}$ is $\tfrac{28.6}{286}=0.1$ of the formula mass. Anhydrous: $0.1\times106=10.6\ \mathrm{g}$; water: $28.6-10.6=18.0\ \mathrm{g}$.
IV
Bleaching powder, crystal water and plaster of Paris.
  • 1 Give the formula and two uses of bleaching powder.
  • 2 What mass of bleaching powder is obtained from $14.2\ \mathrm{g}$ of chlorine? ($\mathrm{Cl}=35.5$, $\mathrm{Ca}=40$, $\mathrm{O}=16\ \mathrm{u}$.)
  • 3 What is water of crystallisation? What do you see when blue crystals of $\mathrm{CuSO_{4}\cdot 5H_{2}O}$ are heated, and when water is then added?
  • 4 Find the percentage by mass of water in washing soda, $\mathrm{Na_{2}CO_{3}\cdot 10H_{2}O}$ (mass $286\ \mathrm{u}$, water $180\ \mathrm{u}$).
  • 5 How is plaster of Paris made from gypsum? Write the equation and the temperature.
  • 6 Write the equation for the setting of plaster of Paris. Why is it kept in moisture-proof containers?
  • 7 What mass of plaster of Paris is obtained from $8.6\ \mathrm{kg}$ of gypsum? ($\mathrm{CaSO_{4}\cdot 2H_{2}O}=172\ \mathrm{u}$, $\mathrm{CaSO_{4}\cdot\tfrac{1}{2}H_{2}O}=145\ \mathrm{u}$.)
  • 8 Challenging. A white powder, mixed with water, warms up slightly and sets into a hard mass. Another white powder dissolves in water to give a basic solution that fizzes with acids. Identify both.
1 $\mathrm{CaOCl_{2}}$. Bleaching cotton and linen, disinfecting drinking water, bleaching wood pulp for paper (any two).
2 $\mathrm{Cl_{2}}=71\ \mathrm{u}$ gives $127\ \mathrm{u}$ of $\mathrm{CaOCl_{2}}$; $14.2\ \mathrm{g}$ is $0.2$ of $71$, so the mass is $0.2\times127=25.4\ \mathrm{g}$.
3 The fixed number of water molecules in the crystal. On heating, the blue crystals turn white and water drops collect on the tube; adding water turns the white powder blue again.
4 $\tfrac{180}{286}\times100=62.9\,\%$.
5 By heating gypsum at $373\ \mathrm{K}$: $\mathrm{CaSO_{4}\cdot 2H_{2}O \rightarrow CaSO_{4}\cdot\tfrac{1}{2}H_{2}O + 1\tfrac{1}{2}H_{2}O}$.
6 $\mathrm{CaSO_{4}\cdot\tfrac{1}{2}H_{2}O + 1\tfrac{1}{2}H_{2}O \rightarrow CaSO_{4}\cdot 2H_{2}O}$. Moisture would set it into hard gypsum before use.
7 $8.6\times\tfrac{145}{172}=7.25\ \mathrm{kg}$ (and $1.35\ \mathrm{kg}$ of water is lost).
8 The first is plaster of Paris. The second is sodium carbonate (or sodium hydrogencarbonate): a basic solution, fizzes with acids giving $\mathrm{CO_{2}}$.
🎯 Exam corner BoardBoard · A–RBoard · Case-based

E1. Board · 1 mark A solution of ammonium chloride has a pH (A) equal to 7   (B) less than 7   (C) greater than 7   (D) that cannot be predicted

Idea $\mathrm{NH_{4}Cl}$ is the salt of a strong acid (HCl) and a weak base ($\mathrm{NH_{4}OH}$): its solution is acidic.
Answer (B).

E2. Board · A–R Assertion (A): Plaster of Paris is stored in a moisture-proof container. Reason (R): It reacts with water to form hard gypsum. Choose: (A) Both A and R are true and R is the correct explanation of A. (B) Both A and R are true but R is not the correct explanation of A. (C) A is true but R is false. (D) A is false but R is true.

Idea Moist air would set the powder into $\mathrm{CaSO_{4}\cdot 2H_{2}O}$, so it is kept dry. R explains A.
Answer (A).

E3. Board · 3 marks Name the process in which brine is electrolysed. Write the balanced equation and name the products, giving one use of each.

Process The chlor-alkali process.
Equation $$\mathrm{2NaCl(aq) + 2H_{2}O(l) \rightarrow 2NaOH(aq) + Cl_{2}(g) + H_{2}(g)}$$
Answer Sodium hydroxide (soap making), chlorine at the anode (disinfecting water), hydrogen at the cathode (fuel, or ammonia for fertilisers).

E4. Board · Case-based Asha bakes two cakes. In cake X she uses baking soda only; in cake Y she uses baking powder. Cake X is yellowish and tastes bitter; cake Y is soft, spongy and tastes normal. (i) What is baking soda, and what does baking powder contain besides it? (1 mark) (ii) Which gas makes cake Y spongy, and how can it be tested? (1 mark) (iii) Write the equation showing why cake X tastes bitter. (2 marks)

(i) Baking soda is sodium hydrogencarbonate, $\mathrm{NaHCO_{3}}$. Baking powder also contains a mild edible acid, such as tartaric acid.
(ii) Carbon dioxide; it turns lime water milky.
Answer (iii) On heating baking soda alone gives sodium carbonate, which is bitter and basic: $$\mathrm{2NaHCO_{3}(s) \rightarrow Na_{2}CO_{3}(s) + H_{2}O(l) + CO_{2}(g)}$$

E5. Board · 1 mark The number of molecules of water of crystallisation per formula unit in gypsum and in plaster of Paris are in the ratio (A) $2:1$   (B) $4:1$   (C) $1:2$   (D) $1:4$

Idea Gypsum is $\mathrm{CaSO_{4}\cdot 2H_{2}O}$ (2 molecules of water); plaster of Paris is $\mathrm{CaSO_{4}\cdot\tfrac{1}{2}H_{2}O}$ ($\tfrac{1}{2}$ molecule). The ratio is $2:\tfrac{1}{2}=4:1$.
Answer (B).

E6. Board · 2 marks Write balanced equations for (a) the preparation of bleaching powder; (b) the action of heat on sodium hydrogencarbonate.

(a) $\mathrm{Cl_{2}(g) + Ca(OH)_{2}(s) \rightarrow CaOCl_{2}(s) + H_{2}O(l)}$
(b) $\mathrm{2NaHCO_{3}(s) \rightarrow Na_{2}CO_{3}(s) + H_{2}O(l) + CO_{2}(g)}$
🔬 Research–Teaching NexusResearch-tutored · optional, two or three evenings

Research question. Which household antacids, baking sodas and cleaning powders in your kitchen are acidic, neutral or basic when dissolved, and does the pH of each agree with the prediction from its parent acid and base?

Why it matters. Manufacturers of foods, medicines and cleaning products control the pH of their products, because it decides how a product tastes, whether it is safe on skin and how well it works. Quality-control laboratories test pH daily. Predicting a pH from a formula, then checking it, is the way chemists decide which salt to use for which job — baking soda for an antacid, washing soda for grease, ammonium chloride in dry cells.

What to do.

  1. Collect eight safe salts: table salt, baking soda, washing soda (from a hardware shop), epsom salt, alum (phitkari), an antacid tablet, a laundry detergent and sugar (a non-salt control).
  2. For each, write down its formula (from the label or an internet search) and predict acidic, neutral or basic from its parent acid and base.
  3. Dissolve one level spoon in half a cup of tap water and test with pH paper or red cabbage juice. Record the colour and pH.
  4. Compare with your predictions and mark each as match or mismatch.
  5. For any mismatch, search for the reason (mixtures, impurities, weak-weak salts).

Tools: pH paper or red cabbage juice, clean cups, spoons, tap or distilled water and a notebook.

Hand in: A table of formula, prediction, observed colour and pH, and a short note on mismatches.

Going further. Heat a spoon of baking soda in a dry steel spoon over a gas flame, let it cool and dissolve it. Is it more basic than before? Which equation explains why?

Instructor note: expect table salt about pH 7 (tap water may read 7–8), baking soda about 8–9, washing soda about 10–11, alum acidic (about 3–4, an aluminium salt of a strong acid), Epsom salt close to neutral to slightly acidic, detergent basic (often 9–10). The heated baking soda should read more basic (sodium carbonate). Common errors: dirty cups, tap water as solvent (itself pH 7–8), too little salt. Use only food-safe samples and do not taste.

🧪 Self-check quiz

0/5 correct

Q1. An aqueous solution of sodium carbonate is

Q2. In the electrolysis of brine, hydrogen gas is formed at the

Q3. When blue crystals of copper sulphate are heated strongly they turn

Q4. The formula of plaster of Paris is

Q5. Bleaching powder is made by passing chlorine gas over