Chapter 4 · Carbon and its Compounds

4.1 Bonding in Carbon: the Covalent Bond

Carbon forms millions of compounds, yet it never forms ions. Find out why carbon shares electrons instead of giving or taking them, how shared pairs make single, double and triple bonds, why covalent compounds behave so differently from salts, and how the same carbon atoms make soft graphite, hard diamond and the football-shaped molecule C60.

Look around you: the paper of this book, the cotton of your shirt, the plastic of your pen, the fuel in a scooter, the sugar in your tea, the medicines in a pharmacy, even your own body — all are built on carbon. Chemists know well over ten million carbon compounds, many more than the compounds of all the other elements put together. Yet carbon is a very ordinary element: it makes up only a tiny fraction of the Earth's crust. What is it about the carbon atom that lets it build so much?

The answer starts with a surprise. In Chapter 3 you learned that atoms become stable by giving or taking electrons and so forming ions. Carbon does not do this. In this section you will see why, and what it does instead: it shares electrons, forming a covalent bond. You will draw electron-dot structures of hydrogen, oxygen, nitrogen, water, methane and carbon dioxide, see why covalent compounds melt at low temperatures and do not conduct electricity, and meet the three famous forms of pure carbon — diamond, graphite and the fullerenes.

Why Carbon Shares: the Covalent Bond

Every atom is most stable when its outermost shell is full — two electrons for the first shell (hydrogen and helium), eight for the later ones (Section 3.2). Sodium reaches this by losing its single outer electron to chlorine. Carbon has electrons in the arrangement 2, 4: four electrons in the outer shell, exactly half-way to eight. Look at what each of the two ionic routes would demand.

Neither route is practical. The way out is for atoms to share electrons, so that each shared pair is counted as belonging to both atoms and completes the outer shell of each.

📘 Definition 4.1 — Covalent bond
A covalent bond is a bond formed between two atoms by the sharing of a pair of electrons, one electron usually coming from each atom. Each shared pair counts towards the outer shell of both atoms. A substance whose atoms are held together by covalent bonds is a covalent compound (or a covalent element, such as $\mathrm{H_{2}}$); its smallest independent unit is a molecule.
📐 Principle 4.1 — Carbon bonds by sharing
A carbon atom (electron arrangement 2, 4) cannot easily gain four electrons or lose four electrons. It therefore completes its outer shell by sharing four electrons with other atoms, forming four covalent bonds. Atoms of other non-metals do the same, but they share only as many electrons as they need: hydrogen (1) shares 1, oxygen (2, 6) shares 2, nitrogen (2, 5) shares 3, chlorine (2, 8, 7) shares 1.

A simple example: two hydrogen atoms. Each has one electron and needs a second to fill its first shell. They bring their electrons together and share them. The shared pair is attracted to both nuclei at once and holds the atoms together, and each hydrogen now has the two electrons of helium. A hydrogen molecule $\mathrm{H_{2}}$ is formed. We draw such pictures with dots for the electrons of one atom and crosses for the electrons of the other; the dots and crosses are only labels, since all electrons are identical.

✏️ Example 1 — Why carbon does not form ions
A carbon atom has 6 protons and the electron arrangement 2, 4. (a) How many electrons would $\mathrm{C^{4-}}$ and $\mathrm{C^{4+}}$ have, and how many protons? (b) Explain why carbon forms neither ion easily. (c) What does it do instead?
(a) $\mathrm{C^{4-}}$: $6+4=10$ electrons, 6 protons. $\mathrm{C^{4+}}$: $6-4=2$ electrons, 6 protons.
(b) In $\mathrm{C^{4-}}$ only 6 protons would hold 10 electrons, which repel each other strongly; in $\mathrm{C^{4+}}$ a huge amount of energy is needed to remove four electrons from a small atom whose nucleus attracts them strongly.
(c) Carbon shares its four outer electrons with other atoms and forms four covalent bonds.

Electron-Dot Structures and Multiple Bonds

To draw the electron-dot structure of a molecule: write the symbols of the atoms side by side; give each atom its outer electrons (as dots or crosses); then pair them up between the atoms so that every atom ends with a full outer shell — 2 electrons for hydrogen, 8 for carbon, nitrogen, oxygen and chlorine. Electrons that are not shared stay on their own atom as lone pairs.

📘 Definition 4.2 — Single, double and triple bonds
A single bond is one shared pair of electrons, drawn as a line: H–H, C–H. A double bond is two shared pairs, drawn as two lines: O=O, O=C=O. A triple bond is three shared pairs, drawn as three lines: N≡N. A drawing of the atoms with a line for each shared pair is a structural formula.
HHOONNH–HsingleO=OdoubleN≡Ntriple
Structural formulas of hydrogen, oxygen and nitrogen: one, two and three shared pairs.
📐 Principle 4.2 — Counting shared pairs
An atom forms as many covalent bonds as it needs electrons to complete its outer shell (its valency): $\mathrm{H}$ 1, $\mathrm{Cl}$ 1, $\mathrm{O}$ 2, $\mathrm{N}$ 3, $\mathrm{C}$ 4. In every correct electron-dot structure the atoms have 2 (hydrogen) or 8 (the others) electrons around them, counting each shared pair for both atoms. The total number of electrons drawn equals the sum of the outer electrons of all the atoms.
MoleculeOuter electrons used (total)Shared pairsLone pairsStructure
hydrogen $\mathrm{H_{2}}$$1+1=2$10H–H
chlorine $\mathrm{Cl_{2}}$$7+7=14$16Cl–Cl
oxygen $\mathrm{O_{2}}$$6+6=12$24O=O
nitrogen $\mathrm{N_{2}}$$5+5=10$32N≡N
water $\mathrm{H_{2}O}$$6+1+1=8$22H–O–H
methane $\mathrm{CH_{4}}$$4+4\times1=8$40C with four C–H
carbon dioxide $\mathrm{CO_{2}}$$4+6+6=16$44O=C=O
OHHCHHHHOCOwatermethanecarbon dioxide
Water is bent, methane has four single C–H bonds, and carbon dioxide has two C=O double bonds (shown here flat; in reality $\mathrm{CO_{2}}$ is straight and methane is three-dimensional).
✏️ Example 2 — Electron-dot structure of water
Describe the electron-dot structure of $\mathrm{H_{2}O}$ and show that every atom has a full outer shell.
Step 1 Oxygen (2, 6) has 6 outer electrons and needs 2 more; each hydrogen (1) has 1 and needs 1 more. So oxygen shares one pair with each hydrogen: two single bonds, H–O–H.
Step 2 Oxygen uses 2 of its 6 electrons in the bonds; the other 4 form two lone pairs on oxygen.
Check Around oxygen: 2 shared pairs $+$ 2 lone pairs $=4$ pairs $=8$ electrons ✓. Around each hydrogen: 1 shared pair $=2$ electrons ✓. Total electrons drawn: $6+1+1=8$ ✓.
✏️ Example 3 — Nitrogen, a triple bond
Nitrogen has the electron arrangement 2, 5. Show that two nitrogen atoms must share three pairs of electrons, and say how many lone pairs the molecule $\mathrm{N_{2}}$ has.
Step 1 Each nitrogen has 5 outer electrons and needs $8-5=3$ more, so each must take part in 3 shared pairs with the other: a triple bond, N≡N.
Step 2 Each atom uses 3 electrons in bonds, leaving $5-3=2$ electrons: one lone pair on each nitrogen.
Check Around each N: 3 shared pairs $+$ 1 lone pair $=4$ pairs $=8$ electrons ✓. Total electrons: $3\times2+2\times2=10=5+5$ ✓. Because the triple bond is so strong, nitrogen gas is very unreactive.
✏️ Example 4 — Carbon dioxide
Explain why the structure of $\mathrm{CO_{2}}$ is O=C=O, and count its shared and lone pairs.
Step 1 Carbon needs 4 more electrons and each oxygen needs 2. Carbon shares two pairs with each oxygen: two double bonds.
Step 2 Shared pairs: $2+2=4$. Each oxygen has $6-2=4$ electrons left, i.e. 2 lone pairs; carbon has none. Lone pairs: $2\times2=4$.
Check Around carbon: 4 shared pairs $=8$ electrons ✓. Around each oxygen: 2 shared $+$ 2 lone pairs $=8$ electrons ✓. Total electrons: $4\times2+4\times2=16=4+6+6$ ✓.
Interactive 1 — Covalent Bond Builder

Choose a molecule and press ▶ Play: the atoms move together and share electrons. Crosses (×) are the electrons of the central atom, dots (●) those of the other atoms. Drag the slider to freeze the picture. Before you press play, predict how many pairs will be shared.

molecule—
shared pairs—
lone pairs—
electrons around each atom—

Properties of Covalent Compounds

In an ionic crystal such as sodium chloride, strong forces hold every ion to its neighbours in all directions, so it takes great heat to melt it. A covalent compound is made of separate molecules. The bonds inside a molecule are strong, but the forces between one molecule and the next are weak. To melt or boil such a substance you only have to pull the molecules apart from each other, not break the bonds within them.

📐 Principle 4.3 — Properties of covalent compounds
  • Low melting and boiling points, because the forces between molecules are weak. Many are gases or liquids at room temperature (methane, ethanol), others are soft solids (candle wax, sugar).
  • Poor conductors of electricity, because the electrons are held in bonds and no ions are present to carry a current.
  • Usually insoluble in water but soluble in organic solvents such as petrol; exceptions such as sugar and ethanol dissolve in water.
  • Exceptions: diamond has a very high melting point, and graphite conducts electricity — both are explained by their structure (next subsection).
SubstanceTypeMelting pointConducts when molten?
sodium chloride $\mathrm{NaCl}$ionic$1074\ \mathrm{K}$ ($801\ ^{\circ}\mathrm{C}$)yes
methane $\mathrm{CH_{4}}$covalent$91\ \mathrm{K}$ ($-182\ ^{\circ}\mathrm{C}$)no
water $\mathrm{H_{2}O}$covalent$273\ \mathrm{K}$ ($0\ ^{\circ}\mathrm{C}$)very poorly
✏️ Example 5 — Ionic or covalent?
Substance X melts at $1074\ \mathrm{K}$ and conducts electricity when molten. Substance Y melts at $178\ \mathrm{K}$ ($-95\ ^{\circ}\mathrm{C}$), does not conduct in either state and dissolves in petrol but not in water. Classify each and justify. Convert $178\ \mathrm{K}$ to °C using $T/\mathrm{K}=t/^{\circ}\mathrm{C}+273$.
X High melting point and conduction when molten show that ions are present and are held strongly: X is an ionic compound (like NaCl).
Y Low melting point, no conduction, soluble in petrol: Y is a covalent compound made of molecules with weak forces between them.
Units $178-273=-95\ ^{\circ}\mathrm{C}$ ✓, a low temperature, typical of a covalent compound.

Allotropes of Carbon: Diamond, Graphite and Fullerene

Pure carbon exists in several forms that look and behave completely differently — one is the hardest natural substance, another is so soft that it leaves a mark on paper. They differ only in how the same carbon atoms are joined.

📘 Definition 4.3 — Allotropes
Allotropes are different forms of the same element in the same physical state, in which the atoms are arranged in different ways. This property is called allotropy. Diamond, graphite and the fullerenes are allotropes of carbon; all three are made of carbon atoms only, and all three burn in oxygen to give only carbon dioxide.
📐 Principle 4.4 — Diamond, graphite and fullerene
  • Diamond: each carbon is bonded to four others (single bonds) in a rigid three-dimensional network. It is the hardest natural substance, has a very high melting point, is transparent and does not conduct electricity, since every outer electron is used in a bond. Uses: jewellery, cutting and drilling tools.
  • Graphite: each carbon is bonded to three others, forming flat hexagonal layers. The layers are held together only weakly and slide over each other, so graphite is soft and slippery; the fourth electron of each atom is free to move, so graphite conducts electricity. Uses: pencil leads, lubricant, electrodes.
  • Fullerene: a molecule of carbon atoms arranged in a hollow cage. The first one found, $\mathrm{C_{60}}$ (1985), has 60 carbon atoms in 20 hexagons and 12 pentagons, like a football, and is named after the architect Buckminster Fuller, whose domes it resembles. Each carbon is bonded to three others.
✏️ Example 6 — Same atoms, same product
(a) Write the equation for the burning of carbon (graphite or diamond) in plenty of oxygen. (b) With $\mathrm{C}=12$, $\mathrm{O}=16\ \mathrm{u}$, what mass of carbon dioxide is formed from $2.4\ \mathrm{g}$ of diamond, and from $2.4\ \mathrm{g}$ of graphite? (c) What does this show? (d) Find the molecular mass of $\mathrm{C_{60}}$.
(a) $$\mathrm{C(s) + O_{2}(g) \rightarrow CO_{2}(g)}$$ Check: C $1=1$; O $2=2$ ✓.
(b) $12\ \mathrm{u}$ of carbon gives $44\ \mathrm{u}$ of $\mathrm{CO_{2}}$, so $2.4\ \mathrm{g}$ is $\tfrac{2.4}{12}=0.2$ of this: $0.2\times44=8.8\ \mathrm{g}$ — the same for diamond and graphite.
(c) Diamond and graphite are both pure carbon; only the arrangement of the atoms differs.
(d) $\mathrm{C_{60}}$: $60\times12=720\ \mathrm{u}$.
Interactive 2 — Allotrope Explorer

Pick an allotrope. The structure turns slowly so you can see it from all sides; in graphite press ▶ and the layers slide over each other. Below it, a sample of the carbon is connected to a battery and a bulb: which form lights the bulb? Predict first.

bonds from each carbon—
hardness—
bulb—
used for—
⚠️ Common mistakes about covalent bonding

1. “Carbon gives away or takes four electrons.” It does neither; it shares.

2. Forgetting lone pairs. Oxygen in water has two lone pairs and nitrogen in $\mathrm{N_{2}}$ has one each; they count towards the octet.

3. “Covalent bonds are weak, so covalent compounds melt easily.” The bonds within molecules are strong; it is the forces between molecules that are weak. In diamond the whole crystal is one giant molecule, which is why it is the exception.

4. “Graphite conducts because it is a metal.” It is a non-metal that conducts because one electron per atom is free.

5. Counting a shared pair once. A shared pair counts for both atoms: in $\mathrm{CH_{4}}$ carbon has four shared pairs, 8 electrons.

Exercises

I
The covalent bond.
  • 1 What is a covalent bond? In which kind of elements does it occur?
  • 2 Write the electron arrangement of C, H, N, O and Cl, and the number of electrons each needs to complete its outer shell.
  • 3 Explain why carbon does not form $\mathrm{C^{4+}}$ or $\mathrm{C^{4-}}$ ions.
  • 4 How many electrons does a carbon atom share in forming methane, and with how many atoms?
  • 5 State the number of shared pairs in $\mathrm{H_{2}}$, $\mathrm{O_{2}}$ and $\mathrm{N_{2}}$ and name the type of bond in each.
  • 6 What is meant by a lone pair? How many lone pairs has each oxygen atom in $\mathrm{O_{2}}$?
  • 7 Why does a shared pair of electrons hold two atoms together?
  • 8 Chlorine atoms have 7 outer electrons. How does the molecule $\mathrm{Cl_{2}}$ form? How many lone pairs does it have?
1 A bond formed by sharing a pair of electrons between two atoms; it occurs between non-metal atoms (and carbon).
2 C 2,4 needs 4; H 1 needs 1; N 2,5 needs 3; O 2,6 needs 2; Cl 2,8,7 needs 1.
3 To form $\mathrm{C^{4-}}$, 6 protons would have to hold 10 electrons; to form $\mathrm{C^{4+}}$ four electrons would have to be removed, needing a great deal of energy. So carbon shares electrons instead.
4 It shares 4 electrons (one with each hydrogen) with 4 hydrogen atoms.
5 $\mathrm{H_{2}}$: 1 pair, single; $\mathrm{O_{2}}$: 2 pairs, double; $\mathrm{N_{2}}$: 3 pairs, triple.
6 A pair of outer electrons that belongs to one atom and is not shared. Each oxygen in $\mathrm{O_{2}}$ has $6-2=4$ electrons left, i.e. 2 lone pairs.
7 The shared pair lies between the nuclei and is attracted to both of them, which pulls the atoms together.
8 Each Cl shares one electron with the other: a single bond. Each Cl keeps $7-1=6$ electrons, i.e. 3 lone pairs, so the molecule has 6 lone pairs.
II
Electron-dot structures.
  • 1 Draw (describe) the electron-dot structure of $\mathrm{H_{2}O}$ and give the number of lone pairs on oxygen.
  • 2 Do the same for $\mathrm{CH_{4}}$ and $\mathrm{CO_{2}}$.
  • 3 How many shared pairs and lone pairs does ammonia, $\mathrm{NH_{3}}$, have?
  • 4 Hydrogen chloride, HCl: give the structural formula and the number of lone pairs.
  • 5 Carbon tetrachloride, $\mathrm{CCl_{4}}$: how many shared pairs and how many lone pairs altogether?
  • 6 Add up the outer electrons and check your drawing of $\mathrm{CO_{2}}$.
  • 7 Explain why a double bond is drawn between the atoms in $\mathrm{O_{2}}$ but a single bond in $\mathrm{H_{2}}$.
  • 8 Challenging. Hydrogen peroxide has the structure H–O–O–H. Count the shared pairs and lone pairs, and check with the total outer electrons.
1 Oxygen shares one pair with each H (H–O–H); it keeps 2 lone pairs. Oxygen has 8 electrons, each H has 2.
2 $\mathrm{CH_{4}}$: carbon shares one pair with each of 4 H (4 single bonds), no lone pairs. $\mathrm{CO_{2}}$: O=C=O, 4 shared pairs, 2 lone pairs on each oxygen.
3 Nitrogen needs 3: three N–H bonds, so 3 shared pairs; $5-3=2$ electrons left on N is 1 lone pair. Total electrons $3\times2+2=8=5+3$ ✓.
4 H–Cl. Hydrogen has no lone pair; chlorine keeps $7-1=6$ electrons, i.e. 3 lone pairs.
5 Carbon shares 4 pairs, one with each Cl: 4 shared pairs. Each Cl has 3 lone pairs: 12 lone pairs. Total electrons: $4\times2+12\times2=32=4+4\times7$ ✓.
6 Outer electrons: $4+6+6=16$. Drawn: 4 shared pairs ($8$) $+$ 4 lone pairs ($8$) $=16$ ✓.
7 Each oxygen needs 2 more electrons for its octet, so two pairs are shared; each hydrogen needs only 1 more, so one pair is shared.
8 Shared pairs: H–O, O–O, O–H = 3. Each O has $6-2=4$ electrons left, i.e. 2 lone pairs: 4 lone pairs. Check: $3\times2+4\times2=14=1+6+6+1$ ✓.
III
Properties of covalent compounds.
  • 1 Why do covalent compounds generally have low melting and boiling points?
  • 2 Why are covalent compounds poor conductors of electricity?
  • 3 A candle melts easily on a flame but a piece of rock salt does not. Explain.
  • 4 Name one covalent solid that is very hard and one that conducts electricity.
  • 5 Naphthalene balls disappear slowly at room temperature. What does this tell you about the forces between naphthalene molecules?
  • 6 Substance P melts at $1273\ \mathrm{K}$ and conducts when dissolved in water. Substance Q melts at $195\ \mathrm{K}$, is a gas at room temperature and does not conduct. Which is ionic and which covalent? Express both melting points in °C.
  • 7 Convert $91\ \mathrm{K}$ to °C and $-95\ ^{\circ}\mathrm{C}$ to K (use $T/\mathrm{K}=t/^{\circ}\mathrm{C}+273$).
  • 8 Name three covalent compounds that are used as fuels.
1 The forces between molecules are weak, so little heat energy is needed to separate them.
2 All electrons are tied up in bonds and there are no ions, so nothing is free to carry a current.
3 Wax is covalent: weak forces between molecules, so it melts at a low temperature. Rock salt is ionic: strong forces between oppositely charged ions, so it melts only at about $1074\ \mathrm{K}$.
4 Very hard: diamond. Conducts electricity: graphite.
5 The forces between the molecules are very weak, so molecules leave the solid easily (it changes straight to vapour).
6 P is ionic (very high melting point, conducts in solution); Q is covalent (gas, no conduction). $1273-273=1000\ ^{\circ}\mathrm{C}$; $195-273=-78\ ^{\circ}\mathrm{C}$.
7 $91-273=-182\ ^{\circ}\mathrm{C}$; $-95+273=178\ \mathrm{K}$.
8 Methane (natural gas), propane/butane (LPG), ethanol (any three).
IV
Allotropes of carbon.
  • 1 What is allotropy? Name three allotropes of carbon.
  • 2 Why is diamond very hard and a non-conductor of electricity?
  • 3 Why does graphite conduct electricity and feel slippery?
  • 4 How many other carbon atoms is each carbon bonded to in diamond, graphite and $\mathrm{C_{60}}$?
  • 5 Describe the shape of a $\mathrm{C_{60}}$ molecule, and find its molecular mass.
  • 6 Why can a pencil write on paper?
  • 7 What mass of carbon dioxide is formed on burning $6\ \mathrm{g}$ of graphite in excess oxygen? ($\mathrm{C}=12$, $\mathrm{O}=16\ \mathrm{u}$.)
  • 8 Applied. Which allotrope would you choose for (a) a glass cutter, (b) the electrode of a dry cell, (c) a lubricant for the moving parts of a hot machine, (d) a ring? Give a reason for each.
  • 9 Challenging. Every atom of $\mathrm{C_{60}}$ has three bonds. How many bonds (lines) are there in the molecule? (Each bond joins two atoms.)
1 The existence of an element in different forms with different arrangements of atoms. Diamond, graphite, fullerene.
2 Each carbon is bonded to four others in a rigid three-dimensional network, which is very hard to break; all four outer electrons are in bonds, so none is free.
3 Each carbon uses three electrons for bonds in a flat layer; the fourth is free to move and carries current. The layers are held together weakly and slide over each other.
4 Diamond 4; graphite 3; $\mathrm{C_{60}}$ 3.
5 A hollow, football-shaped cage of 60 carbon atoms (20 hexagons and 12 pentagons). Molecular mass $=60\times12=720\ \mathrm{u}$.
6 Graphite is soft: layers rub off as the pencil moves and leave a grey mark.
7 $6\ \mathrm{g}$ is $\tfrac{6}{12}=0.5$ of $12\ \mathrm{u}$, so $\mathrm{CO_{2}}$ $=0.5\times44=22\ \mathrm{g}$.
8 (a) diamond (hardest); (b) graphite (conducts); (c) graphite (slippery layers, withstands heat); (d) diamond (brilliant, transparent, hard).
9 $60\times3=180$ bond ends, and each bond has two ends, so $180/2=90$ bonds.
🎯 Exam corner BoardBoard · A–RBoard · Case-basedNEET

E1. Board · 1 mark The number of electrons shared between the two atoms in a nitrogen molecule is (A) 2   (B) 4   (C) 6   (D) 10

Idea Nitrogen needs 3 more electrons, so $\mathrm{N_{2}}$ has a triple bond: 3 shared pairs $=6$ electrons.
Answer (C).

E2. Board · A–R Assertion (A): Graphite conducts electricity but diamond does not. Reason (R): In graphite each carbon atom is bonded to three others, leaving one electron per atom free to move. Choose: (A) Both A and R are true and R is the correct explanation of A. (B) Both A and R are true but R is not the correct explanation of A. (C) A is true but R is false. (D) A is false but R is true.

Idea Both statements are true. In diamond all four electrons are in bonds, so none is free; in graphite the fourth electron is free. R explains A.
Answer (A).

E3. Board · 3 marks Why do carbon compounds have low melting and boiling points and do not conduct electricity? Why is carbon unable to form ionic compounds easily?

Low m.p. and b.p. Carbon compounds are covalent and made of molecules; the forces between molecules are weak and little energy is needed to separate them.
No conduction Their electrons are in shared pairs and there are no ions, so there is no charge carrier.
Not ionic Carbon (2, 4) would have to gain four electrons (hard for a small nucleus of 6 protons to hold) or lose four (needs too much energy), so it shares electrons instead.

E4. Board · Case-based A pencil “lead” is made of graphite, while the drill tip used by a dentist has tiny diamonds. A student learns that both are pure carbon, and that a third form, $\mathrm{C_{60}}$, has 60 atoms. (i) What name is given to these different forms of carbon? (1 mark) (ii) Explain why graphite is soft but diamond is hard. (2 marks) (iii) What is the molecular mass of $\mathrm{C_{60}}$? ($\mathrm{C}=12\ \mathrm{u}$) (1 mark)

(i) Allotropes.
(ii) In diamond every carbon is bonded to four others in a rigid 3-D network. In graphite the carbon atoms form layers held together weakly, so the layers slide.
(iii) $60\times12=720\ \mathrm{u}$.

E5. NEET Foundation. The total number of lone pairs of electrons in one molecule of carbon dioxide is (A) 2   (B) 4   (C) 6   (D) 8

Idea O=C=O: each oxygen has $6-2=4$ non-bonding electrons, i.e. 2 lone pairs; carbon has none. Total $=2\times2=4$ (check: $16$ outer electrons $-8$ in bonds $=8$, i.e. 4 pairs).
Answer (B).

E6. Board · 2 marks State the number of shared pairs and lone pairs in (a) $\mathrm{H_{2}O}$; (b) $\mathrm{NH_{3}}$; (c) $\mathrm{CH_{4}}$.

(a) 2 shared pairs, 2 lone pairs (on oxygen).
(b) 3 shared pairs, 1 lone pair (on nitrogen).
(c) 4 shared pairs, no lone pair.
🔬 Research–Teaching NexusResearch-tutored · optional, one or two evenings

Research question. Can you tell, with only a battery, a bulb and a heat source, whether common kitchen and stationery substances are made of molecules (covalent) or of ions (ionic)?

Why it matters. Materials scientists choose materials by how their atoms are bonded: graphite for battery electrodes and pencils, diamond-coated tools for cutting stone, fullerenes and graphene for new electronics and medicines. The simplest tests — melting behaviour, conduction, solubility — are the first things a chemist does with an unknown solid.

What to do.

  1. Choose six safe samples: table salt, sugar, candle wax, a graphite pencil lead, a pinch of baking soda and a little tap water.
  2. Make a simple tester: a torch bulb, a 3 V battery and two wires with bare ends. Test each solid dry, then each dissolved in water, noting whether the bulb glows (never test mains-powered devices).
  3. Warm a small piece of wax and a pinch of sugar on a metal spoon over a candle flame (an adult present) and note which melts easily.
  4. Classify each sample as ionic, covalent molecular, or “giant covalent”, and explain your evidence.

Tools: torch bulb, 3 V battery, wires, spoon, candle, a notebook.

Hand in: A table of sample, melting behaviour, dry conduction, solution conduction and your classification, with two sentences on any surprise.

Going further. Why does the bulb glow when the pencil lead is connected but not when a diamond-like crystal is? What does that tell you about the electrons?

Instructor note: expect salt dry — no light; salt solution — dim glow; sugar and sugar solution — no light; wax melts easily, no conduction; pencil lead — bulb glows (graphite); baking soda solution — dim glow; tap water — faint or none (dissolved salts). Common errors: wet fingers touching bare wires, weak battery, sugar caramelising and being mistaken for decomposition. Use low-voltage batteries only.

🧪 Self-check quiz

0/5 correct

Q1. Carbon forms covalent bonds rather than ionic bonds because

Q2. How many shared pairs of electrons are there in one molecule of oxygen, O₂?

Q3. Which statement about covalent compounds is generally true?

Q4. Graphite conducts electricity because

Q5. The number of carbon atoms in a molecule of the fullerene named buckminsterfullerene is