Chapter 3 · Metals and Non-metals

3.2 How Metals and Non-metals React: Ionic Compounds

Sodium is a soft metal that reacts violently with water; chlorine is a poisonous gas. Together they make the salt on your table. Learn why metals give away electrons, non-metals take them, and how the resulting ions lock together into crystals with high melting points that conduct only when molten or dissolved.

Drop a piece of sodium into water and it skates about, hissing and sometimes catching fire. Chlorine is a pale green gas so poisonous that it was once used as a weapon. Yet if you let the two react, the product is common salt, the white crystals you sprinkle on your food. How can two dangerous elements combine to make something we eat every day? The answer lies in what happens to their electrons — and the same idea explains magnesium oxide in antacids, calcium chloride in drying agents and thousands of other compounds that metals form with non-metals.

In this section you will see why atoms react at all, how a metal atom hands electrons to a non-metal atom to form ions, how the oppositely charged ions hold together as an ionic bond, and why ionic compounds have such characteristic properties. You will draw electron-shell diagrams for $\mathrm{NaCl}$, $\mathrm{MgCl_{2}}$ and $\mathrm{MgO}$ and learn to write the formula of an ionic compound from the charges of its ions. The ideas return in Class 11 Chemistry, Chapter 4 (Chemical Bonding). A 📘 box near the end, Periodic classification of elements, uses the same electron arrangements to build the periodic table; it is assessed in school but not in the year-end board exam.

Why Atoms React: the Stable Outer Shell

An atom has a tiny nucleus, with positively charged protons, surrounded by negatively charged electrons that move in shells. The shells are filled in order: the first shell (K) holds at most $2$ electrons, the second (L) at most $8$, the third (M) at most $8$ when it is the outermost one (the rule for the first twenty elements). The electrons in the outermost shell are the valence electrons; they decide how the atom reacts.

The noble gases — helium, neon, argon — are almost completely unreactive. Their outer shells are full: helium has $2$ electrons, neon $2,8$ and argon $2,8,8$. This full-shell arrangement is exceptionally stable. Every other atom reacts in a way that gives it the electron arrangement of the nearest noble gas.

📘 Definition 3.5 — Octet and duplet
An atom is stable when its outermost shell is full: with 8 electrons (an octet) or, for the first shell only, with 2 electrons (a duplet). Atoms of other elements gain, lose or share electrons to reach such a noble-gas arrangement. (Sharing is the subject of Section 4.1.)
ElementAtomic numberElectrons in shells K, L, M, NValence electronsNearest noble gas
Lithium Li32, 11helium (2)
Oxygen O82, 66neon (2, 8)
Fluorine F92, 77neon (2, 8)
Neon Ne102, 88—
Sodium Na112, 8, 11neon (2, 8)
Magnesium Mg122, 8, 22neon (2, 8)
Aluminium Al132, 8, 33neon (2, 8)
Chlorine Cl172, 8, 77argon (2, 8, 8)
Argon Ar182, 8, 88—
Calcium Ca202, 8, 8, 22argon (2, 8, 8)

Look at sodium, $2,8,1$. It is one electron more than neon. The easiest way to reach a full outer shell is to lose that single electron: the second shell, already full, becomes the outermost. Chlorine, $2,8,7$, is one electron short of argon, so the easiest way for it is to gain one electron. An atom of magnesium ($2,8,2$) loses two electrons; an atom of oxygen ($2,6$) gains two. Metals have few valence electrons (usually $1$, $2$ or $3$) and tend to lose them; non-metals have $4$ to $7$ and tend to gain.

📘 Definition 3.6 — Ion, cation and anion
An ion is an atom (or group of atoms) that carries an electric charge because it has lost or gained electrons. An atom that loses electrons becomes a positively charged ion, a cation ($\mathrm{Na^{+}}$, $\mathrm{Mg^{2+}}$, $\mathrm{Al^{3+}}$). An atom that gains electrons becomes a negatively charged ion, an anion ($\mathrm{Cl^{-}}$, $\mathrm{O^{2-}}$, $\mathrm{F^{-}}$). Only the electrons change: the number of protons in the nucleus stays the same.
✏️ Example 7 — Reading an ion
(a) Sodium has atomic number $11$. How many protons and electrons are there in an atom of sodium and in the ion $\mathrm{Na^{+}}$? (b) The ion $\mathrm{O^{2-}}$ has $10$ electrons. What is the atomic number of oxygen? (c) Write the electron arrangement of $\mathrm{Mg^{2+}}$ ($Z=12$) and $\mathrm{Cl^{-}}$ ($Z=17$). Which noble gas does each resemble?
(a) A neutral Na atom has $11$ protons and $11$ electrons. $\mathrm{Na^{+}}$ has lost one electron: $11$ protons and $10$ electrons (net charge $+11-10=+1$).
(b) $\mathrm{O^{2-}}$ has gained $2$ electrons, so the neutral atom has $10-2=8$ electrons, hence $8$ protons: atomic number $8$.
(c) $\mathrm{Mg}$ is $2,8,2$; losing $2$ electrons gives $\mathrm{Mg^{2+}}$: $2,8$, like neon. $\mathrm{Cl}$ is $2,8,7$; gaining $1$ electron gives $\mathrm{Cl^{-}}$: $2,8,8$, like argon.
Check Charge of $\mathrm{Mg^{2+}}$: $12$ protons $-$ $10$ electrons $=+2$ ✓. Charge of $\mathrm{Cl^{-}}$: $17-18=-1$ ✓.

Forming Ionic Compounds: NaCl, MgCl₂ and MgO

Now bring sodium and chlorine together. The sodium atom hands its single valence electron to the chlorine atom. Each becomes an ion with a full outer shell: $$\mathrm{Na \rightarrow Na^{+} + e^{-}}\qquad\qquad \mathrm{Cl + e^{-} \rightarrow Cl^{-}}$$ The electron moves from sodium to chlorine, which is shown below with the sodium electron as a dot and the chlorine electrons as crosses.

NaCle⁻ movesNa+Cl−
Sodium (2, 8, 1) gives its outer electron (●) to chlorine (2, 8, 7 — shown ×). The result is Na⁺ (2, 8) and Cl⁻ (2, 8, 8): both have the stable arrangement of a noble gas.

The two ions now have opposite charges, and opposite charges attract. The strong electrostatic force of attraction between a positive and a negative ion is the ionic bond.

📘 Definition 3.7 — Ionic bond and ionic compound
The ionic bond (electrovalent bond) is the electrostatic attraction between oppositely charged ions that are formed when a metal atom transfers electrons to a non-metal atom. A compound held together by ionic bonds is an ionic compound. Ionic compounds form between elements that easily lose electrons (metals) and elements that easily gain them (non-metals), for example $\mathrm{NaCl}$, $\mathrm{MgCl_{2}}$, $\mathrm{CaO}$.
📐 Principle 3.6 — Formation of ions and charge balance
A metal atom with $n$ valence electrons ($n=1,2,3$) loses them to form a cation of charge $+n$; a non-metal atom that is $m$ electrons short of an octet gains $m$ electrons to form an anion of charge $-m$. In an ionic compound the total positive charge equals the total negative charge, so the compound is electrically neutral. The simplest ratio of ions is found by balancing charges: $$\text{number of cations}\times\text{charge}=\text{number of anions}\times\text{charge}$$

Magnesium chloride. A magnesium atom ($2,8,2$) has two valence electrons to lose; a chlorine atom needs only one. So one magnesium atom gives one electron to each of two chlorine atoms: $$\mathrm{Mg \rightarrow Mg^{2+} + 2e^{-}}$$ $$\mathrm{Cl + e^{-} \rightarrow Cl^{-}}\quad(\text{twice})$$ The crystal contains one $\mathrm{Mg^{2+}}$ for every two $\mathrm{Cl^{-}}$: $+2-1-1=0$. The formula is $\mathrm{MgCl_{2}}$: $$\mathrm{Mg(s) + Cl_{2}(g) \rightarrow MgCl_{2}(s)}$$ Magnesium oxide. An oxygen atom ($2,6$) needs two electrons — exactly the two that magnesium offers. One $\mathrm{Mg^{2+}}$ and one $\mathrm{O^{2-}}$ balance, so the formula is $\mathrm{MgO}$: $$\mathrm{2Mg(s) + O_{2}(g) \rightarrow 2MgO(s)}$$ Sodium oxide needs the reverse ratio: oxygen takes two electrons but each sodium offers only one, so two Na atoms are needed per O atom: $\mathrm{2Na^{+}}$ and $\mathrm{O^{2-}}$ give $\mathrm{Na_{2}O}$.

✏️ Example 8 — Sodium chloride from the elements
(a) Write the balanced equation for the formation of sodium chloride from sodium and chlorine gas. (b) Taking $\mathrm{Na}=23\ \mathrm{u}$ and $\mathrm{Cl}=35.5\ \mathrm{u}$, what mass of sodium chloride is formed from $2.3\ \mathrm{g}$ of sodium, and what mass of chlorine gas reacts? (c) What fraction of the mass of sodium chloride is sodium?
(a) $$\mathrm{2Na(s) + Cl_{2}(g) \rightarrow 2NaCl(s)}$$ Check: Na $2=2$; Cl $2=2$. ✓
(b) $2\ \mathrm{Na}=46\ \mathrm{u}$; $\mathrm{Cl_{2}}=71\ \mathrm{u}$; $2\ \mathrm{NaCl}=2\times58.5=117\ \mathrm{u}$. Mass of NaCl $=2.3\times\tfrac{117}{46}=5.85\ \mathrm{g}$. Mass of chlorine $=2.3\times\tfrac{71}{46}=3.55\ \mathrm{g}$.
(c) $\tfrac{23}{58.5}=0.393$, i.e. about $39\%$ of the mass of sodium chloride is sodium.
Check Mass is conserved: $2.3+3.55=5.85\ \mathrm{g}$ ✓.
✏️ Example 9 — Writing formulae by balancing charges
Write the formula of (a) calcium chloride, (b) aluminium oxide, (c) aluminium chloride, using the ions $\mathrm{Ca^{2+}}$, $\mathrm{Al^{3+}}$, $\mathrm{Cl^{-}}$ and $\mathrm{O^{2-}}$. Then find the formula-unit mass of $\mathrm{MgCl_{2}}$ ($\mathrm{Mg}=24\ \mathrm{u}$) and the percentage of magnesium in it.
(a) $\mathrm{Ca^{2+}}$ needs two $\mathrm{Cl^{-}}$: $(+2)+2(-1)=0$. Formula $\mathrm{CaCl_{2}}$.
(b) Find the smallest numbers with $3x=2y$: $x=2$ ions of $\mathrm{Al^{3+}}$ ($+6$) and $y=3$ ions of $\mathrm{O^{2-}}$ ($-6$). Formula $\mathrm{Al_{2}O_{3}}$.
(c) One $\mathrm{Al^{3+}}$ needs three $\mathrm{Cl^{-}}$: $\mathrm{AlCl_{3}}$.
(d) $\mathrm{MgCl_{2}}=24+2\times35.5=95\ \mathrm{u}$. Percentage of Mg $=\tfrac{24}{95}\times100=25.3\%$.
Interactive 1 — Ionic Bond Builder

Pick a compound and press ▶ Play. Watch the valence electrons (●, from the metal) jump into the empty spaces in the outer shell of the non-metal (×, its own electrons). Predict first: how many electrons will move, and what charges will the ions carry?

metal atom(s)—
non-metal atom(s)—
electrons moved—
formula—

Properties of Ionic Compounds

In a crystal of sodium chloride, every $\mathrm{Na^{+}}$ is surrounded by six $\mathrm{Cl^{-}}$ and every $\mathrm{Cl^{-}}$ by six $\mathrm{Na^{+}}$, in a regular three-dimensional pattern that repeats in every direction. There are no separate “$\mathrm{NaCl}$ molecules”; the whole crystal is one giant arrangement of ions held by strong attractions in all directions. From this picture most properties follow.

📐 Principle 3.7 — Properties of ionic compounds
  • Physical state: hard, brittle crystalline solids. The ions are locked in place, so the solid is rigid; but a blow slides one layer of ions over another so that like charges face each other, repel, and the crystal shatters.
  • High melting and boiling points: a great deal of energy is needed to break the strong attractions between ions. Sodium chloride melts at $1074\ \mathrm{K}$ ($801\ ^{\circ}\mathrm{C}$) and boils at $1686\ \mathrm{K}$.
  • Solubility: they are generally soluble in water (which pulls the ions apart) and insoluble in solvents such as kerosene and petrol.
  • Conduction of electricity: they do not conduct in the solid state because the ions cannot move; they conduct when molten or dissolved in water, because the ions are then free to move and carry the current.

Compare three typical melting points: sodium chloride (ions $+1$ and $-1$) melts at $1074\ \mathrm{K}$, calcium chloride at $1045\ \mathrm{K}$, and magnesium oxide, whose ions carry charges $+2$ and $-2$ and attract each other much more strongly, at about $3125\ \mathrm{K}$ ($2852\ ^{\circ}\mathrm{C}$). Ionic compounds therefore stay solid at temperatures at which most metals and all molecular substances have melted.

✏️ Example 10 — Will the bulb glow?
A bulb is connected to a battery and two electrodes. State, with a reason, whether it glows when the electrodes are placed in (a) dry crystals of sodium chloride, (b) molten sodium chloride, (c) sodium chloride dissolved in water, (d) a sugar solution, (e) distilled water.
(a) No: the ions are fixed in the crystal and cannot carry a current.
(b) Yes: melting frees the ions; $\mathrm{Na^{+}}$ moves towards the negative electrode and $\mathrm{Cl^{-}}$ towards the positive one.
(c) Yes: water separates the ions, which move freely: $\mathrm{NaCl(s) \xrightarrow{\text{water}} Na^{+}(aq) + Cl^{-}(aq)}$.
(d), (e) No: sugar dissolves as neutral particles that do not form ions, and distilled water contains almost no ions.
✏️ Example 11 — Why is the melting point of MgO so high?
Explain why magnesium oxide ($\approx3125\ \mathrm{K}$) melts at a much higher temperature than sodium chloride ($1074\ \mathrm{K}$), although both are ionic compounds. Give the ions in each.
Ions $\mathrm{NaCl}$: $\mathrm{Na^{+}}$ and $\mathrm{Cl^{-}}$ (charges $\pm1$). $\mathrm{MgO}$: $\mathrm{Mg^{2+}}$ and $\mathrm{O^{2-}}$ (charges $\pm2$).
Reason The attraction between ions grows with their charges, so the ions of $\mathrm{MgO}$ are held far more strongly than those of $\mathrm{NaCl}$. More energy (a higher temperature) is needed to separate them.
✏️ Example 12 — Is X ionic?
A white crystalline solid X melts at $1100\ \mathrm{K}$, is hard but shatters when hit with a hammer, dissolves in water, and the solution lights a bulb. It does not dissolve in kerosene. (a) Is X ionic? Give reasons. (b) Would you expect X to conduct when solid? When molten? (c) Which type of element combination would produce it?
(a) Yes. High melting point, hard but brittle, soluble in water but not in kerosene, and its solution conducts — all typical of an ionic compound.
(b) Solid: no (ions fixed). Molten: yes (ions mobile).
(c) A metal (which gives electrons) with a non-metal (which accepts them).
Interactive 2 — Does It Conduct?

Choose a substance and press ▶ Play. The left electrode is negative, the right one positive. Predict: will the bulb glow? Look at the particles: are there charged ions, and are they free to move?

particles—
ions free to move?—
bulb—
📘 In the CBSE syllabus — school assessment only (not in the year-end board exam)

Periodic classification of elements is part of the CBSE Class 10 syllabus and is taught and tested in school, but it is not examined in the year-end board exam. It belongs here because it rests on exactly the electron arrangements used in this section. The ideas return in Class 11 Chemistry, Ch. 3 — Classification of Elements and Periodicity in Properties.

Why classify? Well over a hundred elements are known. Learning each one separately would be hopeless, so chemists looked for a pattern that puts similar elements together. Three early attempts led to the table we use today.

1. Döbereiner's triads (1817–1829). Johann Döbereiner noticed groups of three elements with similar properties. Written in order of increasing atomic mass, the atomic mass of the middle element is roughly the average of the other two. Lithium, sodium and potassium ($6.9$, $23.0$ and $39.1\ \mathrm{u}$) form a triad: $\tfrac{6.9+39.1}{2}=23.0$. Calcium, strontium, barium and chlorine, bromine, iodine are two more. Limitation: he could find only three such triads; most of the elements then known did not fit.

2. Newlands' law of octaves (1866). John Newlands arranged the elements known to him in order of increasing atomic mass, starting with hydrogen, and found that every eighth element has properties similar to the first, like the eighth note of a musical scale (sa, re, ga, ma, pa, dha, ni, sa). Lithium is 2nd and sodium 9th; sodium is 9th and potassium 16th. Limitations: the pattern worked only up to calcium; he assumed only $56$ elements existed and none would be discovered; to make it fit he placed two elements in one slot (cobalt and nickel) in the same column as fluorine, chlorine and bromine, which are quite unlike them, while iron, which resembles cobalt and nickel, ended up far away. The noble gases, discovered later, could not be fitted at all.

3. Mendeleev's periodic table (1869). Dmitri Mendeleev took the $63$ elements then known and arranged them by increasing atomic mass, but grouped them above all by their chemical properties, especially the formulae of their oxides and hydrides. His table has eight vertical groups and horizontal periods, and rests on Mendeleev's periodic law: the properties of elements are a periodic function of their atomic masses.

  • Achievements. Where no known element fitted, he left a gap and predicted the missing element. Eka-aluminium (predicted atomic mass $68$, oxide $\mathrm{E_{2}O_{3}}$) was found as gallium ($69.7\ \mathrm{u}$, $\mathrm{Ga_{2}O_{3}}$); eka-boron and eka-silicon became scandium and germanium. He put similar elements together even where it reversed the order of atomic masses, and the noble gases, discovered later, fitted in as a new group without disturbing the rest.
  • Limitations. Hydrogen has no fixed place: like the alkali metals it forms compounds such as $\mathrm{HCl}$ (compare $\mathrm{NaCl}$), but like the halogens it exists as diatomic molecules, $\mathrm{H_{2}}$ (compare $\mathrm{Cl_{2}}$). Isotopes of an element have different atomic masses but the same properties, so ordering by mass gives them different places. Atomic masses do not rise in regular steps, so one cannot tell how many elements lie between two of them; and cobalt ($58.9\ \mathrm{u}$) has to come before nickel ($58.7\ \mathrm{u}$).

4. The Modern Periodic Table. In 1913 Henry Moseley showed that the atomic number $Z$ (the number of protons) is a more fundamental property than atomic mass. The Modern Periodic Law states: the properties of elements are a periodic function of their atomic numbers. Arranged by $Z$, the table has 18 groups (columns) and 7 periods (rows), and the problems of Mendeleev's table disappear: isotopes share one $Z$ and one place, and cobalt ($Z=27$) correctly comes before nickel ($Z=28$). Only hydrogen remains a special case. The position of an element follows directly from its electron arrangement:

  • Elements in the same group have the same number of valence electrons, and therefore similar chemical properties. For the elements of this course, group $=$ valence electrons (groups 1, 2) or valence electrons $+\,10$ (groups 13 to 18); helium, with $2$, sits in group 18 with the other noble gases.
  • Elements in the same period have the same number of occupied shells: period number $=$ number of shells. Period 1 has $2$ elements (the K shell holds $2$ electrons); periods 2 and 3 have $8$ each.

Trends in the Modern Periodic Table (main groups, noble gases left out of the size comparison):

PropertyAcross a period (left → right)Down a group
Valencyrises from $1$ to $4$, then falls to $0$: Na $1$, Mg $2$, Al $3$, Si $4$, P $3$, S $2$, Cl $1$, Ar $0$stays the same (same valence electrons)
Atomic size (radius)decreases: Na $186$ → Cl $99\ \mathrm{pm}$increases: Li $152$, Na $186$, K $231\ \mathrm{pm}$
Metallic characterdecreases (metals on the left, non-metals on the right)increases

Valency is the number of electrons an atom loses, gains or shares to reach an octet: the number of valence electrons if it is $4$ or fewer, otherwise $8$ minus that number. Atomic size falls across a period because the nuclear charge grows while the new electrons enter the same shell, so they are pulled in more tightly; it rises down a group because each step adds a new shell. Metallic character is the tendency to lose electrons. It falls across a period (the larger nuclear charge holds the valence electrons more firmly) and rises down a group (the valence electrons are farther from the nucleus). The metalloids boron, silicon, germanium, arsenic, antimony and tellurium lie along a zig-zag line between metals and non-metals and have intermediate properties. Non-metallic character runs the opposite way, which is why the oxides change from basic on the left (e.g. $\mathrm{Na_{2}O}$) to acidic on the right (e.g. $\mathrm{SO_{2}}$), as in Section 3.1.

📘 Worked example 1 — Testing a triad. The atomic masses of calcium, strontium and barium are $40.1$, $87.6$ and $137.3\ \mathrm{u}$. Do they form a Döbereiner triad? Where do the three elements stand in the Modern Periodic Table?
Solution. The average of the first and third masses is $\tfrac{40.1+137.3}{2}=88.7\ \mathrm{u}$, close to strontium's $87.6\ \mathrm{u}$, and the three elements are chemically alike (reactive metals forming $\mathrm{M^{2+}}$ ions), so yes, they form a triad. All three have $2$ valence electrons: they lie together in group 2, in periods 4, 5 and 6, with atomic size and metallic character increasing from calcium to barium.

📘 Worked example 2 — Placing elements. Elements A, B and C have atomic numbers $11$, $14$ and $17$. (a) Write their electron arrangements and find the group and period of each. (b) Give the valency of each. (c) Which has the largest atoms, and which is the most metallic? (d) Write the formula of the compound of A and C.
Solution. (a) A: $2,8,1$, group 1; B: $2,8,4$, group $4+10=14$; C: $2,8,7$, group $7+10=17$. All have three shells, so all are in period 3. (b) A: $1$; B: $4$; C: $8-7=1$. (c) Size decreases across a period, so A is the largest; A, on the far left, is also the most metallic (it is sodium; B is silicon, a metalloid; C is chlorine, a non-metal). (d) A gives one electron to C: $\mathrm{A^{+}C^{-}}$, formula AC — sodium chloride.

Interactive 3 — Periodic Table Explorer (periods 1–3)

Tap an element to see its electron arrangement, group, period and valency. Switch the view to colour the table by valency, size or metallic character, and predict each trend before you look.

element—
shells—
group · period—
valency—
⚠️ Common mistakes with ionic compounds

1. “Salt conducts electricity.” Solid salt does not. It conducts only when molten or dissolved, because only then are the ions free to move.

2. Writing $\mathrm{NaCl}$ as a molecule. An ionic compound is a lattice of ions; $\mathrm{NaCl}$ is a formula unit giving the ratio $1:1$.

3. Wrong charges in the formula. $\mathrm{Al_{2}O_{3}}$ is $2\times(+3)+3\times(-2)=0$, not $\mathrm{AlO}$. Balance the charges, not the atoms of a diagram.

4. Mixing up cation and anion. Cations are positive because they have lost electrons; anions are negative because they have gained them. Metals form cations, non-metals form anions.

5. Changing the nucleus. Gaining or losing electrons never changes the number of protons.

Exercises

I
Atoms and ions.
  • 1 Write the electron arrangement (K, L, M) of Li, O, F, Na, Mg, Al and Cl.
  • 2 Why are the noble gases almost completely unreactive?
  • 3 Define an ion, a cation and an anion, with one example of each.
  • 4 An element has atomic number $13$. Write its electron arrangement, the ion it forms and the noble gas whose arrangement the ion has.
  • 5 Write the symbol (with charge) of the ion formed by (a) oxygen, (b) fluorine, (c) magnesium, (d) sodium, (e) chlorine.
  • 6 Why does sodium lose an electron rather than gain seven?
  • 7 Give the number of protons and electrons in (a) $\mathrm{Cl^{-}}$ ($Z=17$), (b) $\mathrm{Mg^{2+}}$ ($Z=12$), (c) $\mathrm{O^{2-}}$ ($Z=8$).
  • 8 Do the electrons or the protons change when a sodium atom becomes a sodium ion? How does the size of the charge arise?
1 Li $2,1$; O $2,6$; F $2,7$; Na $2,8,1$; Mg $2,8,2$; Al $2,8,3$; Cl $2,8,7$.
2 Their outermost shells are full (helium $2$; neon, argon $8$), a very stable arrangement; they have no tendency to gain, lose or share electrons.
3 Ion: a charged atom (or group) formed by gain or loss of electrons. Cation: positive ion, e.g. $\mathrm{Na^{+}}$. Anion: negative ion, e.g. $\mathrm{Cl^{-}}$.
4 $2,8,3$; it loses $3$ electrons to give $\mathrm{Al^{3+}}$ ($2,8$), which resembles neon.
5 (a) $\mathrm{O^{2-}}$; (b) $\mathrm{F^{-}}$; (c) $\mathrm{Mg^{2+}}$; (d) $\mathrm{Na^{+}}$; (e) $\mathrm{Cl^{-}}$.
6 Losing $1$ electron is far easier than gaining $7$; losing it leaves the stable $2,8$ arrangement of neon.
7 (a) $17$ protons, $18$ electrons; (b) $12$ protons, $10$ electrons; (c) $8$ protons, $10$ electrons.
8 Only the electrons change (one is lost); the $11$ protons remain. The charge is the excess of protons over electrons: $11-10=+1$.
II
Forming ionic compounds.
  • 1 Describe, with equations for each atom, how sodium chloride forms from sodium and chlorine.
  • 2 Why do two chlorine atoms combine with one magnesium atom in $\mathrm{MgCl_{2}}$?
  • 3 Show the formation of magnesium oxide from a magnesium atom and an oxygen atom, giving the charges on the ions.
  • 4 Write the formula of (a) sodium oxide, (b) calcium chloride, (c) aluminium oxide, (d) aluminium chloride, (e) magnesium oxide.
  • 5 Write a balanced equation with state symbols for the formation of calcium chloride from calcium and chlorine.
  • 6 What mass of sodium chloride is formed when $2.3\ \mathrm{g}$ of sodium reacts completely with chlorine? ($\mathrm{Na}=23\ \mathrm{u}$, $\mathrm{Cl}=35.5\ \mathrm{u}$)
  • 7 Find the formula-unit mass of $\mathrm{MgCl_{2}}$ and the percentage of magnesium in it. ($\mathrm{Mg}=24\ \mathrm{u}$, $\mathrm{Cl}=35.5\ \mathrm{u}$)
  • 8 Calcium (atomic number $20$) reacts with oxygen. Give its electron arrangement, the ions formed, and the formula and equation of the product.
  • 9 Why is the formula of aluminium oxide $\mathrm{Al_{2}O_{3}}$ and not $\mathrm{AlO}$?
1 $\mathrm{Na \rightarrow Na^{+} + e^{-}}$ (2, 8, 1 → 2, 8); $\mathrm{Cl + e^{-} \rightarrow Cl^{-}}$ (2, 8, 7 → 2, 8, 8). The ions attract: $\mathrm{Na^{+}Cl^{-}}$, formula $\mathrm{NaCl}$.
2 Magnesium loses $2$ electrons, each chlorine gains only $1$; so two Cl atoms are needed to take both electrons: $\mathrm{Mg^{2+}}$ and $2\ \mathrm{Cl^{-}}$.
3 $\mathrm{Mg \rightarrow Mg^{2+} + 2e^{-}}$ (2, 8, 2 → 2, 8); $\mathrm{O + 2e^{-} \rightarrow O^{2-}}$ (2, 6 → 2, 8). Formula $\mathrm{MgO}$.
4 (a) $\mathrm{Na_{2}O}$; (b) $\mathrm{CaCl_{2}}$; (c) $\mathrm{Al_{2}O_{3}}$; (d) $\mathrm{AlCl_{3}}$; (e) $\mathrm{MgO}$.
5 $\mathrm{Ca(s) + Cl_{2}(g) \rightarrow CaCl_{2}(s)}$
6 $\mathrm{2Na + Cl_{2} \rightarrow 2NaCl}$: $46\ \mathrm{u}$ Na gives $117\ \mathrm{u}$ NaCl. Mass $=2.3\times\tfrac{117}{46}=5.85\ \mathrm{g}$.
7 $24+71=95\ \mathrm{u}$. Percentage of Mg $=\tfrac{24}{95}\times100=25.3\%$.
8 Ca: $2,8,8,2$; it loses $2$ electrons to form $\mathrm{Ca^{2+}}$ ($2,8,8$); oxygen forms $\mathrm{O^{2-}}$. Formula $\mathrm{CaO}$: $$\mathrm{2Ca(s) + O_{2}(g) \rightarrow 2CaO(s)}$$
9 The ions are $\mathrm{Al^{3+}}$ and $\mathrm{O^{2-}}$. $\mathrm{AlO}$ would have charge $+3-2=+1$; $\mathrm{Al_{2}O_{3}}$ gives $+6-6=0$.
III
Properties of ionic compounds.
  • 1 Why are ionic solids hard but also brittle?
  • 2 Why do ionic compounds have high melting points?
  • 3 Why does sodium chloride conduct electricity when molten or dissolved in water but not when solid?
  • 4 In which of these liquids does sodium chloride dissolve: water, kerosene, petrol?
  • 5 A bulb is connected in series with electrodes. Which of the following make it glow: solid KCl, molten KCl, KCl solution, sugar solution?
  • 6 A compound has a high melting point, is brittle, and its solution conducts electricity. A second compound is a soft solid that melts at $330\ \mathrm{K}$, does not dissolve in water and does not conduct. Which is likely ionic?
  • 7 The melting points of sodium chloride, calcium chloride and magnesium oxide are $1074\ \mathrm{K}$, $1045\ \mathrm{K}$ and about $3125\ \mathrm{K}$. Convert them to degrees Celsius and suggest why magnesium oxide is so high.
  • 8 Applied. Pure distilled water hardly lights a bulb, but when a little common salt is dissolved in it the bulb glows brightly. Explain. Why are electrical appliances never touched with wet hands?
1 Strong attractions lock the ions in a rigid lattice (hard). A blow slides a layer so that like charges meet and repel, and the crystal splits (brittle).
2 A lot of energy is needed to overcome the strong electrostatic attraction between the oppositely charged ions.
3 A current needs moving charges. In the solid, ions are fixed; when molten or dissolved they are free to move.
4 It dissolves in water, but not in kerosene or petrol.
5 Molten KCl and KCl solution make it glow. Solid KCl does not (fixed ions), and sugar solution does not (no ions).
6 The first is ionic. The second, soft with a low melting point and non-conducting, is not.
7 $1074-273=801\ ^{\circ}\mathrm{C}$; $1045-273=772\ ^{\circ}\mathrm{C}$; $3125-273=2852\ ^{\circ}\mathrm{C}$. $\mathrm{MgO}$ has ions of charge $\pm2$, which attract much more strongly than the $\pm1$ ions of $\mathrm{NaCl}$.
8 Salt dissolves to give free $\mathrm{Na^{+}}$ and $\mathrm{Cl^{-}}$ ions, which carry the current. Wet hands carry dissolved salts (ions) from sweat, so they conduct and can carry a dangerous current.
IV
Putting it together.
  • 1 Element X has electron arrangement $2,8,3$ and element Y has $2,6$. Name the type of bond between them and write the formula of the compound.
  • 2 Potassium has atomic number $19$ ($2,8,8,1$). Write the formulae of potassium chloride and potassium oxide and balanced equations for their formation from the elements.
  • 3 Compare $\mathrm{Na^{+}}$ and a neon atom: what do they have in common and how do they differ?
  • 4 Why can two metals not form an ionic compound with each other?
  • 5 Challenging. Molten sodium chloride is electrolysed between two electrodes. Towards which electrode does each ion move, and what is formed at each? Write the overall equation.
1 X (aluminium) loses $3$ electrons, Y (oxygen) gains $2$: an ionic bond; $2\times(+3)+3\times(-2)=0$, formula $\mathrm{Al_{2}O_{3}}$.
2 $\mathrm{KCl}$ and $\mathrm{K_{2}O}$. $\mathrm{2K(s) + Cl_{2}(g) \rightarrow 2KCl(s)}$; $\mathrm{4K(s) + O_{2}(g) \rightarrow 2K_{2}O(s)}$.
3 Both have $10$ electrons arranged $2,8$. Na⁺ has $11$ protons (charge $+1$); neon has $10$ protons (neutral).
4 Metals tend to lose electrons; neither would accept the electrons the other gives away.
5 $\mathrm{Na^{+}}$ moves to the negative electrode (cathode), where sodium forms; $\mathrm{Cl^{-}}$ moves to the positive electrode (anode), where chlorine gas forms. $$\mathrm{2NaCl(l) \rightarrow 2Na(l) + Cl_{2}(g)}$$
V
📘 School assessment only (not in the year-end board exam). Periodic classification.
  • 1 Lithium, sodium and potassium have atomic masses $6.9$, $23.0$ and $39.1\ \mathrm{u}$. Show that they form a Döbereiner triad.
  • 2 State Newlands' law of octaves and give two of its limitations.
  • 3 Give two achievements and two limitations of Mendeleev's periodic table.
  • 4 State the Modern Periodic Law. How does it settle the problem of where to place isotopes?
  • 5 An element has atomic number $16$. Find its electron arrangement, group, period and valency, and say whether it is a metal or a non-metal.
  • 6 Arrange $\mathrm{Mg}$, $\mathrm{Na}$, $\mathrm{Cl}$ and $\mathrm{P}$ in order of decreasing atomic size, and say which is the most metallic.
1 $\tfrac{6.9+39.1}{2}=23.0\ \mathrm{u}$, equal to the atomic mass of sodium, and the three are similar, soft, reactive metals: a triad.
2 In order of increasing atomic mass, every eighth element resembles the first. Limitations (any two): it worked only up to calcium; it assumed only $56$ elements; cobalt and nickel shared a slot and sat with fluorine, chlorine and bromine; iron was placed far from cobalt and nickel.
3 Achievements: gaps left for undiscovered elements whose properties were predicted (gallium, scandium, germanium); the noble gases fitted in later as a new group. Limitations: no fixed position for hydrogen; no place for isotopes; atomic masses do not increase regularly (cobalt before nickel).
4 The properties of elements are a periodic function of their atomic numbers. Isotopes have the same atomic number, so they occupy the same place.
5 $2,8,6$: $6$ valence electrons, so group $6+10=16$; three shells, so period 3; valency $8-6=2$. It gains electrons readily: a non-metal (sulphur).
6 All are in period 3, and size decreases from left to right: $\mathrm{Na}\gt\mathrm{Mg}\gt\mathrm{P}\gt\mathrm{Cl}$. Sodium, on the far left, is the most metallic.
🎯 Exam corner BoardBoard · A–RBoard · Case-basedJEE Main / NEET

E1. Board · 1 mark Which of the following is not a property of ionic compounds? (A) high melting point   (B) conduct electricity in the molten state   (C) soluble in water   (D) conduct electricity in the solid state

Idea Ions in a solid are fixed in place and cannot carry current; they move only in the molten state or in solution.
Answer (D).

E2. Board · A–R Assertion (A): Sodium chloride conducts electricity in the molten state but not in the solid state. Reason (R): In the molten state the ions are free to move. Choose: (A) Both A and R are true and R is the correct explanation of A. (B) Both A and R are true but R is not the correct explanation of A. (C) A is true but R is false. (D) A is false but R is true.

Idea Both are true: conduction needs mobile charge carriers, which are present in the molten state only.
Answer (A).

E3. Board · 3 marks The atomic numbers of elements A and B are $12$ and $17$. (a) Write their electron arrangements. (b) Write the formula of the compound formed and name the type of bond. (c) Show the transfer of electrons.

(a) A (Mg): $2,8,2$; B (Cl): $2,8,7$.
(b) Mg loses $2$ electrons, each Cl gains $1$: formula $\mathrm{MgCl_{2}}$, an ionic bond.
(c) $\mathrm{Mg \rightarrow Mg^{2+} + 2e^{-}}$ (2, 8, 2 → 2, 8); each Cl: $\mathrm{Cl + e^{-} \rightarrow Cl^{-}}$ (2, 8, 7 → 2, 8, 8); the two $\mathrm{Cl^{-}}$ ions attach to one $\mathrm{Mg^{2+}}$.

E4. Board · Case-based Three solids are tested. A: melting point $1074\ \mathrm{K}$, dissolves in water, solution conducts, solid does not. B: melting point $340\ \mathrm{K}$, insoluble in water, soluble in petrol, does not conduct in any state. C: melting point $1356\ \mathrm{K}$ (copper), insoluble, conducts as a solid. (i) Which is ionic, and which is a metal? (2 marks) (ii) Why does A not conduct when solid? (1 mark) (iii) If A is sodium chloride, write the equation for the formation of its ions in water. (1 mark)

(i) A is ionic (high melting point, soluble in water, conducts in solution). C is a metal (conducts as a solid). B is neither: low melting point, soluble in petrol, a non-conductor.
(ii) Its ions are fixed in the crystal and cannot move.
(iii) $\mathrm{NaCl(s) \xrightarrow{\text{water}} Na^{+}(aq) + Cl^{-}(aq)}$.

E5. JEE Main / NEET Foundation. Of the ions $\mathrm{Na^{+}}$, $\mathrm{Mg^{2+}}$, $\mathrm{F^{-}}$, $\mathrm{O^{2-}}$ and $\mathrm{Cl^{-}}$, how many have the electron arrangement $2,8$? (A) 3   (B) 4   (C) 5   (D) 2

Idea $\mathrm{Na^{+}}$: $11-1=10$ electrons, $2,8$. $\mathrm{Mg^{2+}}$: $12-2=10$, $2,8$. $\mathrm{F^{-}}$: $9+1=10$, $2,8$. $\mathrm{O^{2-}}$: $8+2=10$, $2,8$. $\mathrm{Cl^{-}}$: $17+1=18$, $2,8,8$.
Answer (B) — four of the five.

E6. Board · 2 marks Why do ionic compounds have high melting points and why are they soluble in water but not in kerosene?

Idea Strong electrostatic attraction between oppositely charged ions needs much energy to overcome.
Answer Water molecules can pull the ions apart and surround them, so ionic compounds dissolve in water; kerosene cannot, so they do not dissolve in it.
🔬 Research–Teaching NexusResearch-tutored · optional, two evenings

Research question. Which household solutions carry an electric current, and how does the concentration of dissolved salt change the brightness of an LED in a home-made conductivity tester?

Why it matters. Conductivity meters are used all over the world to test whether drinking water, river water and soil water are too salty. Hospitals rely on carefully balanced ionic solutions in drips, sports drinks replace salts lost in sweat, and the electrical signals in your nerves are carried by moving $\mathrm{Na^{+}}$ and $\mathrm{K^{+}}$ ions. A simple tester shows that the more ions in water, the better it conducts.

What to do.

  1. Build a tester: two graphite pencil leads (or two clean iron nails) held apart in a cork, connected in series with a $4.5\ \mathrm{V}$ battery and an LED with a suitable resistor (ask a teacher).
  2. Test: distilled or boiled and cooled water, tap water, sugar solution, salt solution, baking-soda solution, vinegar, lemon juice and cooking oil. Record whether the LED glows and how brightly.
  3. Make salt solutions with $1$, $2$, $4$ and $8$ teaspoons of salt in a glass of water and rank the brightness.
  4. Dissolve and test a pinch of washing soda and a pinch of sugar for comparison.

Tools: Battery, LED, resistor, wires, pencil leads, plastic cups, salt, sugar, and household liquids.

Hand in: A table of substances with brightness (none / dim / bright), a graph of brightness against salt added, and a paragraph explaining the results in terms of ions.

Going further. Does brightness keep rising without limit? Does the LED glow for solid salt pressed between the electrodes?

Instructor note: expect no glow for sugar, oil and distilled water; a faint glow for tap water; and stronger glow for salt, baking soda and washing soda, increasing with concentration but levelling off. Lemon juice and vinegar contain ions from acids and glow somewhat. Solid salt will not light the LED (but a damp crystal may, slightly). Adult supervision for the electrical set-up; use a battery only, never mains.

🧪 Self-check quiz

0/5 correct

Q1. The electron arrangement of a magnesium ion, $\mathrm{Mg^{2+}}$, is

Q2. Which of the following is the correct formula of aluminium oxide?

Q3. Solid sodium chloride does not conduct electricity because

Q4. In the formation of $\mathrm{MgO}$ from Mg and O, how many electrons does each magnesium atom give away?

Q5. Which statement about ionic compounds is correct?