12.1 The Molecular Nature of Matter and the Behaviour of Gases
Matter is made of molecules, and in a gas they are far apart and almost free. Count them with the mole and the Avogadro constant, and every dilute gas obeys one equation: $pV=nRT=Nk_BT$.
Put a drop of ink into a glass of still water and, without any stirring, the colour slowly spreads through the whole glass. Squeeze the air in a bicycle pump with your finger over the outlet and it pushes back harder the more you squeeze; let it go and it springs back. A sealed packet of crisps carried up a mountain puffs up like a pillow. These everyday observations are hard to explain if matter is a smooth, continuous jelly. They are easy to explain if matter is made of an enormous number of tiny particles that are always moving โ and, in a gas, are mostly empty space with a few particles flying about in it.
This section collects the evidence for that molecular picture and puts numbers on it: how big molecules are, how far apart they sit in a solid, a liquid and a gas, and how to count them with the mole and the Avogadro constant. Then it re-reads the gas laws you met with the ideal-gas equation in Chapter 10 (Thermal Properties of Matter) โ Boyle's law, Charles's law, Avogadro's hypothesis and Dalton's law of partial pressures โ in the language of molecules, through the molecular form of the gas equation, $pV=Nk_BT$. Section 12.2 will then explain why gases obey it.
The molecular nature of matter
The idea that matter is made of indivisible particles is very old โ it appears in ancient Indian philosophy (Kanada's paramanu) and in Greek thought (Democritus's atomos) โ but for two thousand years it was a speculation. It became science around 1800, when chemists found that elements always combine in fixed, simple ratios by mass (Dalton's atomic theory), and that gases react in simple ratios by volume (Gay-Lussac). Today the evidence is overwhelming: the jittering of pollen grains in water (Brownian motion, explained by Einstein in 1905 as the grains being knocked about by water molecules), X-ray diffraction from crystals, and microscopes that image individual atoms.
Atoms are about $10^{-10}\ \text{m}$ ($1$ รฅngstrรถm, $1$ ร ) across. In solids they are packed tightly, at a spacing of about $2$ ร , held near fixed positions by strong forces, though they vibrate about them. In liquids the spacing is about the same, but the molecules are not tied to fixed positions and can slide past one another. In gases at ordinary pressures the molecules are about ten times further apart, tens of รฅngstrรถms, so the forces between them are negligible except during brief collisions: each molecule travels freely in a straight line until it hits another molecule or a wall. That is why gases are easy to compress, fill any container and mix freely, and why their behaviour is so simple.
One mole ($1\ \text{mol}$) of a substance is the amount that contains exactly $N_A$ elementary entities (atoms or molecules), where the Avogadro constant is
$$N_A=6.022\times10^{23}\ \text{mol}^{-1}\quad(\text{we use }6.02\times10^{23}\ \text{mol}^{-1}).$$A sample of $N$ molecules contains $n=\dfrac{N}{N_A}$ moles. The molar mass $M$ is the mass of one mole: numerically the molecular mass in grams, so $M=0.028\ \text{kg/mol}$ for nitrogen, $\mathrm{N_2}$. The mass of one molecule is $m=\dfrac{M}{N_A}$, and a sample of mass $M_s$ contains $n=\dfrac{M_s}{M}$ moles.
An ideal gas is a model gas in which (i) the molecules are so small compared with their separation that their own volume is negligible, and (ii) they exert no forces on one another except during collisions, which are elastic and take negligible time. Real gases behave almost ideally when they are dilute โ at low pressure and at temperatures well above the temperature at which they liquefy.
The gas equation in molecular form
Experiments on a fixed amount of any dilute gas give three simple laws, which you met with the ideal-gas equation in Chapter 10 (Thermal Properties of Matter). They are worth restating, because each says something about molecules.
For a fixed amount of a dilute gas:
- Boyle's law: at constant temperature, $pV=\text{constant}$, so $p_1V_1=p_2V_2$;
- Charles's law: at constant pressure, $V\propto T$, so $\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$;
- pressure law (Gay-Lussac): at constant volume, $p\propto T$, so $\dfrac{p_1}{T_1}=\dfrac{p_2}{T_2}$,
where $T$ is the absolute (kelvin) temperature. Together they say $\dfrac{pV}{T}$ is constant: $\dfrac{p_1V_1}{T_1}=\dfrac{p_2V_2}{T_2}$.
The molecular reading is natural. In Boyle's law, squeezing the gas into half the volume packs twice as many molecules into each cubic metre, so twice as many hit each square metre of wall every second: the pressure doubles. In the pressure law, heating the gas makes the molecules move faster, so they hit the walls harder and more often. The constant $\dfrac{pV}{T}$ is found to be proportional to the amount of gas โ and, remarkably, it is the same for every gas when the amount is measured in moles, or simply by counting molecules.
For $n$ moles, or $N=nN_A$ molecules, of an ideal gas at absolute temperature $T$,
$$pV=nRT=Nk_BT,$$where $R=8.31\ \text{J mol}^{-1}\text{K}^{-1}$ is the gas constant and
$$k_B=\frac{R}{N_A}=\frac{8.31}{6.02\times10^{23}}=1.38\times10^{-23}\ \text{J/K}$$is the Boltzmann constant โ the gas constant per molecule. Dividing by $V$, the pressure depends only on the number density $n_V=\dfrac NV$ (molecules per cubic metre) and the temperature: $p=n_Vk_BT$. In terms of the density $\rho$ and molar mass $M$, $p=\dfrac{\rho RT}{M}$.
The equation contains no property of the particular gas. A cubic metre of hydrogen and a cubic metre of carbon dioxide at the same temperature and pressure hold the same number of molecules, even though each $\mathrm{CO_2}$ molecule is $22$ times heavier. Notice the care needed with symbols: $n$ is the number of moles, $N$ the number of molecules, and we write $n_V$ for the number density.
- Convert every temperature to kelvin: $T=t_C+273$ (use $273.15$ when the data justify it).
- Use absolute pressure. A tyre gauge reads gauge pressure: add atmospheric pressure first, and subtract it again at the end if a gauge reading is asked for.
- If the amount of gas is fixed, use $\dfrac{p_1V_1}{T_1}=\dfrac{p_2V_2}{T_2}$ โ any consistent units for $p$ and $V$ will do, since they cancel. If the amount is asked for or changes, use $pV=nRT$ (or $Nk_BT$) in SI units.
- Check the direction: hotter at constant volume means higher pressure; compressed at constant temperature means higher pressure.
Avogadro's hypothesis and Dalton's law of partial pressures
Since $pV=Nk_BT$ contains no property of the gas, equal values of $p$, $V$ and $T$ force equal values of $N$. Avogadro guessed this in 1811, from the simple volume ratios in which gases react, long before anyone could count molecules.
Equal volumes of all gases at the same temperature and pressure contain the same number of molecules. In particular, one mole of any ideal gas at standard temperature and pressure (STP: $273\ \text{K}$ and $1\ \text{atm}=1.013\times10^5\ \text{Pa}$) occupies the molar volume
$$V_m=\frac{RT}{p}=\frac{8.31\times273}{1.013\times10^5}=2.24\times10^{-2}\ \text{m}^3=22.4\ \text{L}.$$The number density at STP is $n_V=\dfrac{p}{k_BT}=2.69\times10^{25}\ \text{m}^{-3}$ for every gas.
When several gases share a container โ air is mainly nitrogen, oxygen and argon โ each kind of molecule behaves as if the others were not there, because in an ideal gas the molecules do not interact. Each gas hits the walls and contributes its own share of the pressure.
The partial pressure of a gas in a mixture is the pressure it would exert if it alone filled the whole volume at the same temperature. For a mixture of ideal gases the total pressure is the sum of the partial pressures:
$$p=p_1+p_2+\dots=(n_1+n_2+\dots)\frac{RT}{V}.$$Each partial pressure is the total pressure times the gas's mole fraction: $p_1=\dfrac{n_1}{n_1+n_2+\dots}\,p$.
Real gases and the limits of the ideal-gas model
How good is $pV=nRT$? Measure $\dfrac{pV}{nRT}$ for a real gas over a range of pressures. For an ideal gas this ratio would be exactly $1$ at every pressure. For real gases it is very close to $1$ at low pressures โ within a fraction of a per cent at atmospheric pressure โ but deviates at hundreds of atmospheres. Two molecular effects compete:
- Attraction between molecules pulls each molecule near a wall back towards the rest of the gas, so it hits the wall less hard: the pressure is lower than ideal and $\dfrac{pV}{nRT}\lt1$. This matters most at low temperatures, when the molecules move slowly, and it is what eventually makes a gas liquefy.
- The finite size of molecules takes up part of the container, leaving less free space, so at very high densities the pressure is higher than ideal and $\dfrac{pV}{nRT}\gt1$.
Both effects vanish as the gas is made more dilute. So real gases approach ideal behaviour at low pressures and high temperatures, and every gas law in this chapter is a low-density law. Air at room conditions obeys it to better than $0.1\%$.
1. Celsius in the gas laws. $V\propto T$ and $p\propto T$ hold for kelvin temperatures only. Doubling the temperature from $20\ ^\circ\text{C}$ to $40\ ^\circ\text{C}$ raises $T$ by under $7\%$.
2. Gauge pressure in $pV=nRT$. Always use absolute pressure; convert back at the end if a gauge reading is wanted.
3. Mixing up $n$ and $N$. $pV=nRT$ uses moles; $pV=Nk_BT$ uses the number of molecules. They differ by a factor of $6.02\times10^{23}$.
4. Units of volume and molar mass. In SI, $V$ is in $\text{m}^3$ ($1\ \text{L}=10^{-3}\ \text{m}^3$, $1\ \text{cm}^3=10^{-6}\ \text{m}^3$) and $M$ in $\text{kg/mol}$ ($28\ \text{g/mol}=0.028\ \text{kg/mol}$).
5. "Equal masses, equal pressures." At the same $V$ and $T$, pressure is proportional to the number of moles, not the mass: $1\ \text{g}$ of hydrogen exerts $16$ times the pressure of $1\ \text{g}$ of oxygen.
Exercises
Take $R=8.31\ \text{J mol}^{-1}\text{K}^{-1}$, $k_B=1.38\times10^{-23}\ \text{J/K}$, $N_A=6.02\times10^{23}\ \text{mol}^{-1}$, $1\ \text{atm}=1.013\times10^5\ \text{Pa}$, STP $=273\ \text{K}$ and $1\ \text{atm}$, and $g=9.8\ \text{m/s}^2$. Treat all gases as ideal unless told otherwise.
- 1 How many molecules are there in $1.0\ \text{g}$ of water ($M=18\ \text{g/mol}$)?
- 2 Find the mass of one oxygen molecule, $\mathrm{O_2}$ ($M=32\ \text{g/mol}$).
- 3 Copper has molar mass $63.5\ \text{g/mol}$ and density $8.96\times10^3\ \text{kg/m}^3$. Estimate the spacing between neighbouring copper atoms.
- 4 How many nitrogen molecules are there in a $2.0\ \text{L}$ flask of nitrogen at STP?
- 5 Using the molecular picture, explain why gases are easy to compress but liquids and solids are not.
- 6 Treat each molecule of a gas at STP as a sphere of diameter $3.0\times10^{-10}\ \text{m}$. What fraction of the volume of the gas do the molecules themselves occupy?
- 7 What is Brownian motion, and why is it evidence that the molecules of a liquid are in constant random motion?
- 1 A gas occupies $3.0\ \text{L}$ at $2.0\times10^5\ \text{Pa}$. It is compressed at constant temperature to $1.2\ \text{L}$. Find its new pressure.
- 2 A balloon has a volume of $2.0\ \text{L}$ at $27\ ^\circ\text{C}$. It is cooled to $-73\ ^\circ\text{C}$ at constant pressure. Find its new volume.
- 3 A steel gas cylinder is filled to an absolute pressure of $1.5\times10^7\ \text{Pa}$ at $15\ ^\circ\text{C}$. It is safe up to $1.8\times10^7\ \text{Pa}$. Find the highest safe temperature in $^\circ\text{C}$.
- 4 How many moles of gas are in a $5.0\ \text{L}$ vessel at $2.0\ \text{atm}$ and $300\ \text{K}$?
- 5 Find the density of oxygen ($M=32\ \text{g/mol}$) at $27\ ^\circ\text{C}$ and $2.0\times10^5\ \text{Pa}$.
- 6 Show that $pV=nRT$ and $pV=Nk_BT$ are the same equation, and calculate $k_B$ from $R$ and $N_A$.
- 7 A $50\ \text{L}$ oxygen cylinder at $300\ \text{K}$ shows a gauge pressure of $1.5\times10^6\ \text{Pa}$. After use, still at $300\ \text{K}$, it shows $5.0\times10^5\ \text{Pa}$. What mass of oxygen was used? (Atmospheric pressure $1.0\times10^5\ \text{Pa}$.)
- 8 For a fixed amount of ideal gas, sketch (a) $p$ against $V$ at constant $T$, (b) $pV$ against $p$ at constant $T$, (c) $V$ against Celsius temperature at constant $p$. Where does the graph in (c) cut the temperature axis?
- 1 Find the volume of $4.4\ \text{g}$ of carbon dioxide ($M=44\ \text{g/mol}$) at STP.
- 2 Two identical flasks at the same temperature and pressure contain hydrogen and oxygen respectively. Find the ratio of the numbers of molecules, and of the masses of gas, in them.
- 3 A vessel contains $0.20\ \text{mol}$ of nitrogen and $0.30\ \text{mol}$ of oxygen at a total pressure of $2.5\times10^5\ \text{Pa}$. Find the partial pressure of each gas.
- 4 Dry air is $78\%$ nitrogen, $21\%$ oxygen and $1\%$ argon by number of molecules. Find the partial pressure of oxygen at sea level ($1.013\times10^5\ \text{Pa}$) and at the summit of Everest ($3.3\times10^4\ \text{Pa}$).
- 5 A $2.0\ \text{L}$ vessel of gas at $3.0\times10^5\ \text{Pa}$ is connected by a thin tube to a $3.0\ \text{L}$ vessel at $1.0\times10^5\ \text{Pa}$, at the same temperature. Find the final common pressure.
- 6 Under what conditions does a real gas deviate most from ideal behaviour? Explain why $\dfrac{pV}{nRT}$ can be either less than or greater than $1$.
- 7 Using the composition in part 4, find the average molar mass of dry air and its density at STP.
- 1 (Modelling) A hot-air balloon has an envelope of volume $2000\ \text{m}^3$. The outside air is at $27\ ^\circ\text{C}$ and $1.013\times10^5\ \text{Pa}$ (molar mass $29\ \text{g/mol}$); the air inside is heated to $100\ ^\circ\text{C}$ at the same pressure. Find the densities of the outside and inside air and the greatest total mass (envelope, basket and passengers) the balloon can lift.
- 2 A vessel of gas at $27\ ^\circ\text{C}$ is fitted with a valve that keeps its pressure constant by letting gas escape. The vessel is heated to $127\ ^\circ\text{C}$. What fraction of the gas escapes?
- 3 A narrow tube closed at one end contains a $20\ \text{cm}$ column of air trapped by a $10\ \text{cm}$ thread of mercury. With the tube horizontal the air column is $20\ \text{cm}$ long. Find its length when the tube is vertical (a) open end up, (b) open end down. Atmospheric pressure is $76\ \text{cm}$ of mercury; the temperature is constant.
- 4 The outlet of a syringe is sealed with $60\ \text{mL}$ of air inside at $1.0\times10^5\ \text{Pa}$. The plunger, of area $4.0\ \text{cm}^2$, is pushed in slowly until the volume is $20\ \text{mL}$. Find the pressure of the air and the extra force needed to hold the plunger there.
- 5 A sealed packet of crisps contains $1.0\ \text{L}$ of air at $1.0\times10^5\ \text{Pa}$ and $300\ \text{K}$. It is carried up a mountain where the pressure is $7.0\times10^4\ \text{Pa}$ and the temperature $280\ \text{K}$. Assuming the packet is slack enough not to resist, find its new volume.
- 6 Estimate the number of air molecules in a classroom $10\ \text{m}\times8.0\ \text{m}\times3.0\ \text{m}$ at $300\ \text{K}$ and $1.013\times10^5\ \text{Pa}$, and the mass of the air.
E1. Board ยท 2 marks State Avogadro's hypothesis. Use the equation $pV=Nk_BT$ to show that it holds for ideal gases, and find the volume of one mole of an ideal gas at STP.
E2. NEET A closed vessel contains $8.0\ \text{g}$ of oxygen and $7.0\ \text{g}$ of nitrogen at $27\ ^\circ\text{C}$. The total pressure is $2.0\ \text{atm}$. The partial pressure of nitrogen is (a) $0.93\ \text{atm}$ (b) $1.0\ \text{atm}$ (c) $1.07\ \text{atm}$ (d) $2.0\ \text{atm}$
E3. JEE Main (Numerical value) A $10.0\ \text{L}$ flask at $300\ \text{K}$ contains a mixture of helium ($M=4\ \text{g/mol}$) and nitrogen ($M=28\ \text{g/mol}$) of total mass $20.0\ \text{g}$, at a total pressure of $6.0\ \text{atm}$. Find the mass of helium in the flask, in grams, to the nearest integer. ($R=8.31\ \text{J mol}^{-1}\text{K}^{-1}$, $1\ \text{atm}=1.013\times10^5\ \text{Pa}$.)
E4. JEE Advanced (One or more correct) For ideal gases, which statements are correct? (A) At the same temperature and pressure, $1\ \text{L}$ of hydrogen and $1\ \text{L}$ of carbon dioxide contain the same number of molecules. (B) At the same temperature and pressure, the density of a gas is proportional to its molar mass. (C) If the Celsius temperature of a gas in a rigid container is doubled, its pressure doubles. (D) For a fixed mass of a given gas, $\dfrac{p}{\rho T}$ is constant, whatever the volume.
E5. NEET JEE Main A gas at $27\ ^\circ\text{C}$ occupies a volume $V$. At constant pressure it is heated to $327\ ^\circ\text{C}$. Its new volume is (a) $1.1V$ (b) $1.5V$ (c) $2V$ (d) $12.1V$
E6. Board ยท Case study A weather balloon is filled with helium at ground level, where the pressure is $1.0\times10^5\ \text{Pa}$ and the temperature $300\ \text{K}$; its volume there is $5.0\ \text{m}^3$. It rises to a height where the pressure is $2.5\times10^4\ \text{Pa}$ and the temperature $225\ \text{K}$. (i) Which gas law (or laws) must you use to find its new volume, and why? [1] (ii) Find the new volume, assuming the envelope stretches freely. [2] (iii) How many moles of helium does the balloon contain? [1]
Research question. Can a sealed plastic syringe and a set of kitchen weights verify Boyle's law โ and measure the pressure of the atmosphere at the same time?
Why it matters. Boyle's law is the working principle of the spirometers that doctors use to test lung capacity, of the pressure sensors in car tyres and weather stations, and of every scuba regulator. The idea of finding an unknown pressure from the intercept of a straight-line graph is the same one that laboratories use to locate absolute zero and to calibrate gauges.
What to do. Use a $20\ \text{mL}$ or $50\ \text{mL}$ plastic syringe. Measure the internal diameter of its barrel (or divide a marked volume by the length it occupies) to find the plunger area $A$.
- Draw in air to a mid-scale mark and seal the nozzle firmly (a cap or a blob of putty). Note the volume $V_0$.
- Clamp the syringe vertically, nozzle down, and hang or stand known masses $m$ on the plunger: $0.5$, $1.0$, $1.5$, $2.0\ \text{kg}$. Twist the plunger gently before each reading to reduce friction, wait, and record the volume $V$.
- The gas pressure is $p=p_a+\dfrac{mg}{A}$. Boyle's law says $p\propto\dfrac1V$, so plot $\dfrac{mg}{A}$ (the extra pressure) on the $y$-axis against $\dfrac1V$ on the $x$-axis.
- The graph should be a straight line whose $y$-intercept is $-p_a$. Read off the atmospheric pressure and compare with a weather report for your town.
- Repeat the readings while removing the masses. Do the two sets agree? What does any difference tell you about friction?
Tools: Syringe and cap or putty, a clamp stand, kitchen weights or water bottles of known mass, a ruler, a spreadsheet for the graph and a straight-line fit.
Hand in: Your table of $m$, $V$, $\dfrac1V$ and $\dfrac{mg}{A}$; the graph with its best-fit line; your value of $p_a$ with an estimate of its uncertainty; and a paragraph on the main sources of error (friction, leaks, the dead volume in the nozzle, temperature).
Going further. Put the sealed syringe in water baths at different temperatures with a fixed load and test Charles's law. Extrapolate your $V$โ$T$ line: how close to $-273\ ^\circ\text{C}$ does it cross the axis?
๐งช Self-check quiz
Q1. The Boltzmann constant $k_B$ is equal to
Q2. When a gas is compressed to half its volume at constant temperature, its pressure doubles because
Q3. At STP, one mole of hydrogen and one mole of oxygen occupy
Q4. A mixture of $2\ \text{mol}$ of helium and $3\ \text{mol}$ of argon has a total pressure of $5.0\ \text{atm}$. The partial pressure of helium is
Q5. A real gas behaves most nearly like an ideal gas at