Chapter 1 · Units and Measurement

1.1 Physical Quantities and the International System of Units

Every measurement is a number times a unit. The SI builds every unit in physics from seven base units, scaled by prefixes in powers of ten.

On 23 July 1983 an Air Canada Boeing 767 ran out of fuel at about 12 000 m over Manitoba. Nothing had leaked. The ground crew had worked out the fuel load correctly — as a number — but multiplied by a density in pounds per litre when the aircraft's computer expected kilograms. The aircraft took off with less than half the fuel the crew believed they had, and the pilots glided it to a safe landing on a disused runway at Gimli. A number without the right unit is not a measurement: it is a trap.

Physics is built on measurement. Before we can say that a force is "large" or a speed is "dangerous", we must compare it with an agreed standard — a unit. This section sets up the language every later chapter uses: what a physical quantity is, the seven base units of the International System (SI), how all other units are built from them, how prefixes such as kilo- and micro- scale them, and how to convert reliably from one unit to another.

Physical quantities and units

Length, mass, time, speed, force, energy, temperature: each of these can be measured, and each measurement is a comparison with a chosen standard of the same kind. When we write "the corridor is $12\ \text{m}$ long" we mean that the corridor is twelve times as long as the standard called the metre.

📘 Definition 1.1 — Physical quantity and unit
A physical quantity is a property of a body or a process that can be measured. A unit is an agreed standard of the same kind, chosen as a reference. Every measured value of a quantity $Q$ is written as $$Q = n\,u,$$ where $u$ is the unit and $n$ is the numerical value of $Q$ in that unit. For a fixed quantity, a larger unit gives a smaller numerical value: if the same $Q$ is measured in two units, $n_1u_1=n_2u_2$, so $n\propto\dfrac1u$.

For example, $Q = 1.5\ \text{km} = 1500\ \text{m}$: the kilometre is $1000$ times larger than the metre, so the numerical value is $1000$ times smaller. The relation $n_1u_1 = n_2u_2$ is the whole secret of unit conversion.

A unit system needs only a few independent standards. Once length, mass and time have units, speed (length ÷ time), acceleration (speed ÷ time) and force (mass × acceleration) all get units automatically.

📘 Definition 1.2 — Base and derived quantities
The base quantities of a unit system are a small set of quantities chosen to be independent of one another; their units are the base units. Every other quantity is a derived quantity: it is defined by an equation in terms of base quantities, and its derived unit is the matching product of powers of base units.

The International System of Units (SI)

Several unit systems grew up historically — the CGS system (centimetre, gram, second), the FPS system (foot, pound, second) and the MKS system (metre, kilogram, second). Science and almost every country now use the Système Internationale d'Unités (French for "International System of Units"), abbreviated SI, agreed by the General Conference on Weights and Measures. It has seven base quantities.

Base quantitySI unitSymbolFixed by (since 2019)
lengthmetremspeed of light $c$
masskilogramkgPlanck constant $h$
timesecondscaesium-133 frequency $\Delta\nu_{\text{Cs}}$
electric currentampereAelementary charge $e$
thermodynamic temperaturekelvinKBoltzmann constant $k_B$
amount of substancemolemolAvogadro constant $N_A$
luminous intensitycandelacdluminous efficacy $K_{\text{cd}}$

Until 2019 the kilogram was a platinum–iridium cylinder kept near Paris; if it gained a few atoms of dirt, the mass of everything else in the world changed on paper. Today every base unit is defined by giving an exact value to a constant of nature, so any well-equipped laboratory anywhere can realise it. In plain words:

Two more units measure angles. They are dimensionless derived units (once called "supplementary units"), and they appear constantly in rotation, waves and optics.

📘 Definition 1.3 — Radian and steradian

The plane angle $d\theta$ subtended at the centre of a circle of radius $r$ by an arc of length $ds$ is $d\theta=\dfrac{ds}{r}$. Its unit is the radian (rad): one radian is the angle subtended by an arc equal in length to the radius. A full circle is $\dfrac{2\pi r}{r}=2\pi\ \text{rad}=360^\circ$.

The solid angle $d\Omega$ subtended at the centre of a sphere of radius $r$ by a patch of its surface of area $dA$ is $d\Omega=\dfrac{dA}{r^2}$. Its unit is the steradian (sr). The whole sphere subtends $\dfrac{4\pi r^2}{r^2}=4\pi\ \text{sr}$.

🧭 Rules for writing SI units
  1. Unit symbols are upright and never take a plural "s" or a full stop: $5\ \text{kg}$, not "5 kgs." or "5 Kg".
  2. Leave a space between the number and the unit: $3.0\ \text{m}$. (Exception: the degree signs, $30^\circ$.)
  3. A unit named after a person has a capital symbol but a lower-case name: newton (N), joule (J), kelvin (K) — and temperature in kelvin is "$273\ \text{K}$", never "°K".
  4. Write products with a space or a centred dot ($\text{N m}$ or $\text{N·m}$) and quotients with a solidus or a negative power ($\text{m/s}$ or $\text{m s}^{-1}$). Use at most one solidus: $\text{m/s}^2$, not "m/s/s".
  5. Do not mix symbols and names ("km/hour"), and do not invent abbreviations ("sec", "hrs", "mps"). Watch the space: $\text{m s}^{-1}$ is metre per second but $\text{ms}^{-1}$ is "per millisecond".
✏️ Example 1 — Base or derived?
Classify each quantity as base or derived and give its SI unit in terms of base units: (a) area, (b) amount of substance, (c) speed, (d) density, (e) temperature.
(a) Area = length × length: derived, unit $\text{m}^2$.
(b) Amount of substance is one of the seven base quantities: unit $\text{mol}$.
(c) Speed = distance ÷ time: derived, unit $\text{m/s}=\text{m s}^{-1}$.
(d) Density = mass ÷ volume: derived, unit $\text{kg/m}^3=\text{kg m}^{-3}$.
(e) Thermodynamic temperature is a base quantity: unit $\text{K}$. (The degree Celsius is a derived unit with the same size as the kelvin; $T/\text{K}=t/^\circ\text{C}+273.15$.)
✏️ Example 2 — Plane and solid angle
(a) A sprinter runs $1.5\ \text{m}$ along a circular track lane of radius $2.5\ \text{m}$ measured from the centre of a small practice circle. What angle, in radians and degrees, does she turn through? (b) A $0.50\ \text{m}^2$ solar sensor is part of a sphere of radius $2.0\ \text{m}$ centred on a lamp. What solid angle does it subtend at the lamp, and what fraction of the lamp's light (emitted equally in all directions) does it catch?
(a) Radians $\theta=\dfrac{s}{r}=\dfrac{1.5\ \text{m}}{2.5\ \text{m}}=0.60\ \text{rad}$ — the metres cancel, so the radian is a pure number.
(a) Degrees $\theta=0.60\times\dfrac{180^\circ}{\pi}=34^\circ$ (to 2 significant figures).
(b) Solid angle $\Omega=\dfrac{A}{r^2}=\dfrac{0.50\ \text{m}^2}{(2.0\ \text{m})^2}=0.125\ \text{sr}\approx0.13\ \text{sr}$.
(b) Fraction The whole sphere is $4\pi\ \text{sr}$, so the fraction is $\dfrac{0.125}{4\pi}=9.9\times10^{-3}$, about $1\%$. Check with areas: $\dfrac{0.50}{4\pi(2.0)^2}=\dfrac{0.50}{50.3}\approx0.0099$. ✓
Interactive 1 — Radians and Steradians Do Not Care About Size

Left: an arc of length $s$ on a circle of radius $r$. Right: a cap of area $A$ on a sphere of radius $r$, cut out by a cone of half-angle $\alpha$. Press Play to make the circle and sphere grow and shrink: $s$ and $A$ change, but $\theta=s/r$ and $\Omega=A/r^2$ stay fixed — that is why angles are pure numbers.

radius $r$—
arc $s$ / angle $\theta=s/r$—
$\theta$ in degrees—
cap area $A$ / $\Omega=A/r^2$—

Derived units, prefixes and scientific notation

A derived unit is obtained by following the defining equation of the quantity and replacing every quantity by its SI unit. Force is defined by $F=ma$, so its unit is $\text{kg}\times\text{m/s}^2=\text{kg m s}^{-2}$. This combination is used so often that it has its own name, the newton (N). The same idea gives every unit in this course.

QuantityDefining relationNamed unitIn base units
force$F=ma$newton, N$\text{kg m s}^{-2}$
work, energy$W=Fd$joule, J $=\text{N m}$$\text{kg m}^2\text{s}^{-2}$
power$P=W/t$watt, W $=\text{J/s}$$\text{kg m}^2\text{s}^{-3}$
pressure, stress$p=F/A$pascal, Pa $=\text{N/m}^2$$\text{kg m}^{-1}\text{s}^{-2}$
frequency$\nu=1/T$hertz, Hz$\text{s}^{-1}$
electric charge$q=It$coulomb, C$\text{A s}$

Physics deals with sizes from the proton ($\sim10^{-15}\ \text{m}$) to the observable universe ($\sim10^{26}\ \text{m}$). We handle them with scientific notation, $a\times10^{b}$ with $1\le a\lt10$, and with SI prefixes, each of which multiplies a unit by a power of ten.

PrefixSymbolFactorPrefixSymbolFactor
decid$10^{-1}$decada$10^{1}$
centic$10^{-2}$hectoh$10^{2}$
millim$10^{-3}$kilok$10^{3}$
microµ$10^{-6}$megaM$10^{6}$
nanon$10^{-9}$gigaG$10^{9}$
picop$10^{-12}$teraT$10^{12}$
femtof$10^{-15}$petaP$10^{15}$
attoa$10^{-18}$exaE$10^{18}$

(The list continues in steps of $10^3$: zepto/zetta $10^{\mp21}$, yocto/yotta $10^{\mp24}$, and since 2022 ronto/ronna $10^{\mp27}$ and quecto/quetta $10^{\mp30}$.) Two warnings: the kilogram already carries a prefix, so prefixes for mass are attached to the gram ($1\ \text{mg}=10^{-6}\ \text{kg}$, not "1 µkg"); and a prefix belongs to the unit before any power is applied, so $1\ \text{cm}^3=(10^{-2}\ \text{m})^3=10^{-6}\ \text{m}^3$.

📐 Principle 1.1 — Converting units with factors of one
Because $n_1u_1=n_2u_2$, any equation between units can be written as a fraction equal to one, for example $\dfrac{1000\ \text{m}}{1\ \text{km}}=1$ or $\dfrac{1\ \text{h}}{3600\ \text{s}}=1$. Multiplying a quantity by such fractions changes its numerical value and its unit together but not the quantity itself. Choose each fraction so that the unwanted unit cancels; raise the fraction to the same power as the unit (for $\text{cm}^3$ use $\left(\tfrac{1\ \text{m}}{100\ \text{cm}}\right)^3$).
Interactive 2 — The Prefix Ladder: from Protons to Galaxies

The axis is logarithmic: each tick is a factor of $10$ and each prefix band is a factor of $1000$. Press Play to sweep the pointer across forty orders of magnitude, or drag the slider. The readouts write the same value in scientific notation and with the best-fitting prefix (for mass the prefix goes on the gram).

scientific notation (SI unit)—
with a prefix—
nearest object—
✏️ Example 3 — Highway speeds
A speed limit is $90\ \text{km/h}$. Express it in $\text{m/s}$. Then find the general rule for converting between $\text{km/h}$ and $\text{m/s}$.
Factors of one $$90\ \frac{\text{km}}{\text{h}}\times\frac{1000\ \text{m}}{1\ \text{km}}\times\frac{1\ \text{h}}{3600\ \text{s}}=\frac{90\,000}{3600}\ \frac{\text{m}}{\text{s}}=25\ \text{m/s}.$$
Rule $1\ \text{km/h}=\dfrac{1000}{3600}\ \text{m/s}=\dfrac{5}{18}\ \text{m/s}$, so multiply by $\tfrac{5}{18}$ to go from km/h to m/s, and by $\tfrac{18}{5}=3.6$ to go back.
Check $25\times3.6=90$. ✓ A useful anchor: $36\ \text{km/h}=10\ \text{m/s}$ and $72\ \text{km/h}=20\ \text{m/s}$.
✏️ Example 4 — Density in SI units
Mercury has density $13.6\ \text{g/cm}^3$. Express this in $\text{kg/m}^3$.
Set up Convert grams to kilograms and $\text{cm}^3$ to $\text{m}^3$; the length factor must be cubed.
Convert $$13.6\ \frac{\text{g}}{\text{cm}^3}\times\frac{1\ \text{kg}}{1000\ \text{g}}\times\left(\frac{100\ \text{cm}}{1\ \text{m}}\right)^3=13.6\times\frac{10^6}{10^3}\ \frac{\text{kg}}{\text{m}^3}=1.36\times10^4\ \text{kg/m}^3.$$
Check Water is $1.0\ \text{g/cm}^3=1.0\times10^3\ \text{kg/m}^3$, so "multiply by $1000$" is the rule; mercury is $13.6$ times denser than water. ✓
✏️ Example 5 — What your electricity bill measures
A household uses $250$ "units" of electricity in a month; one unit is $1\ \text{kWh}$ (a power of one kilowatt used for one hour). (a) How many joules is that? (b) A $1.5\ \text{kW}$ water heater runs $40$ minutes a day for $30$ days. How many units does it use?
kWh in joules $1\ \text{kWh}=(1000\ \text{W})(3600\ \text{s})=3.6\times10^6\ \text{W s}=3.6\times10^6\ \text{J}$.
(a) $250\ \text{kWh}=250\times3.6\times10^6\ \text{J}=9.0\times10^8\ \text{J}$.
(b) Time $=30\times40\ \text{min}=1200\ \text{min}=20\ \text{h}$; energy $=1.5\ \text{kW}\times20\ \text{h}=30\ \text{kWh}$, i.e. $30$ units ($1.08\times10^8\ \text{J}$).
✏️ Example 6 — Spot the errors
A lab report says: "The trolley (mass 2 Kg) moved 3 mtrs in 1.5 secs, so its speed was 2 ms⁻¹ and the room was at 300 °K." Rewrite it correctly.
Symbols "Kg" → $\text{kg}$ (lower-case k: capital K is the kelvin); "mtrs" → $\text{m}$; "secs" → $\text{s}$ (no plural, no invented abbreviations).
Spacing "ms⁻¹" means per millisecond. Write $\text{m s}^{-1}$ or $\text{m/s}$.
Kelvin "°K" → $\text{K}$: kelvin takes no degree sign.
Corrected "The trolley (mass $2\ \text{kg}$) moved $3\ \text{m}$ in $1.5\ \text{s}$, so its speed was $2\ \text{m/s}$ and the room was at $300\ \text{K}$."
⚠️ Common mistakes with units

1. Forgetting to raise the conversion factor to a power. $1\ \text{m}^2=10^4\ \text{cm}^2$, not $100\ \text{cm}^2$; $1\ \text{L}=10^{-3}\ \text{m}^3$.

2. Prefixes on the kilogram. $1\ \text{g}=10^{-3}\ \text{kg}$ and $1\ \text{mg}=10^{-6}\ \text{kg}$. Always convert to $\text{kg}$ before using $F=ma$ or $K=\tfrac12mv^2$.

3. Substituting numbers in mixed units. Convert every quantity to SI before substituting; then the answer comes out in SI automatically.

Exercises

I
Quantities and SI units.
  • 1 Classify as base or derived and give the SI unit: (a) volume, (b) electric current, (c) density, (d) temperature.
  • 2 Express the newton in SI base units.
  • 3 Express the joule in SI base units, starting from $W=Fd$.
  • 4 Express the watt in SI base units.
  • 5 Express the pascal in SI base units.
  • 6 Momentum is mass × velocity. Find its SI unit and show that it equals $\text{N s}$.
  • 7 Which are written correctly? "5 Kg", "12 sec", "3.0 m/s", "20 newtons", "273 K", "273 °K". Correct the others.
  • 8 Why is the kilogram the only SI base unit whose name contains a prefix, and what does that mean for writing $10^{-6}\ \text{kg}$?
1 (a) derived, $\text{m}^3$; (b) base, $\text{A}$; (c) derived, $\text{kg m}^{-3}$; (d) base, $\text{K}$.
2 $\text{N}=\text{kg}\times\text{m s}^{-2}=\text{kg m s}^{-2}$.
3 $\text{J}=\text{N}\times\text{m}=\text{kg m}^2\text{s}^{-2}$.
4 $\text{W}=\text{J/s}=\text{kg m}^2\text{s}^{-3}$.
5 $\text{Pa}=\text{N/m}^2=\text{kg m}^{-1}\text{s}^{-2}$.
6 $\text{kg}\times\text{m/s}=\text{kg m s}^{-1}$; and $\text{N s}=\text{kg m s}^{-2}\times\text{s}=\text{kg m s}^{-1}$. ✓
7 Correct: "3.0 m/s" and "273 K". Fix: "5 kg", "12 s", "20 N" (or "20 newtons" in words — the symbol never takes an s), "273 K".
8 Historically the gram was the base, but it was too small for practical standards, so the kilogram became the base unit. Prefixes still attach to the gram: $10^{-6}\ \text{kg}=10^{-3}\ \text{g}=1\ \text{mg}$ (never "1 µkg").
II
Unit conversions. Use factors of one and show the cancelling.
  • 1 $54\ \text{km/h}$ in $\text{m/s}$.
  • 2 $25\ \text{m/s}$ in $\text{km/h}$.
  • 3 $2.5\ \text{g/cm}^3$ in $\text{kg/m}^3$.
  • 4 One day in seconds.
  • 5 One year of $365.25$ days in seconds.
  • 6 $500\ \text{cm}^2$ in $\text{m}^2$.
  • 7 $1.0\ \text{L}$ in $\text{m}^3$ (one litre is $1000\ \text{cm}^3$).
  • 8 $g=9.8\ \text{m/s}^2$ in $\text{km/h}^2$.
1 $54\times\tfrac{5}{18}=15\ \text{m/s}$.
2 $25\times3.6=90\ \text{km/h}$.
3 $2.5\times\tfrac{10^6}{10^3}=2.5\times10^3\ \text{kg/m}^3$.
4 $24\times60\times60=86\,400\ \text{s}=8.64\times10^4\ \text{s}$.
5 $365.25\times86\,400=3.156\times10^7\ \text{s}$ (a handy approximation: $\pi\times10^7\ \text{s}$).
6 $500\ \text{cm}^2\times\left(\tfrac{1\ \text{m}}{100\ \text{cm}}\right)^2=500\times10^{-4}\ \text{m}^2=5.00\times10^{-2}\ \text{m}^2$.
7 $1000\ \text{cm}^3\times10^{-6}\ \tfrac{\text{m}^3}{\text{cm}^3}=1.0\times10^{-3}\ \text{m}^3$.
8 $9.8\ \tfrac{\text{m}}{\text{s}^2}\times\tfrac{1\ \text{km}}{1000\ \text{m}}\times\left(\tfrac{3600\ \text{s}}{1\ \text{h}}\right)^2=\tfrac{9.8\times1.296\times10^7}{10^3}=1.3\times10^5\ \text{km/h}^2$ (more precisely $1.27\times10^5$).
III
Prefixes, scientific notation and angles.
  • 1 Write with a suitable prefix: (a) $4.5\times10^{-6}\ \text{m}$, (b) $3.2\times10^{9}\ \text{Hz}$, (c) $2.0\times10^{-9}\ \text{s}$, (d) $6.8\times10^{5}\ \text{W}$.
  • 2 Write in SI base units in scientific notation: (a) $15\ \text{mg}$, (b) $250\ \text{µs}$, (c) $40\ \text{nm}$.
  • 3 How many square metres is $1\ \text{µm}^2$?
  • 4 A point on the rim of a wheel of radius $0.35\ \text{m}$ moves $1.4\ \text{m}$ along the rim. Through what angle has the wheel turned, in radians and degrees?
  • 5 Convert $60^\circ$ to radians and $2.5\ \text{rad}$ to degrees.
  • 6 A detector of area $2.0\ \text{cm}^2$ faces a small source $0.50\ \text{m}$ away. Find the solid angle it subtends and the fraction of the source's radiation (emitted equally in all directions) that it receives.
1 (a) $4.5\ \text{µm}$; (b) $3.2\ \text{GHz}$; (c) $2.0\ \text{ns}$; (d) $680\ \text{kW}$ (or $0.68\ \text{MW}$).
2 (a) $15\times10^{-3}\ \text{g}=1.5\times10^{-5}\ \text{kg}$; (b) $2.5\times10^{-4}\ \text{s}$; (c) $4.0\times10^{-8}\ \text{m}$.
3 $(10^{-6}\ \text{m})^2=10^{-12}\ \text{m}^2$ — the prefix is squared too.
4 $\theta=\tfrac{1.4}{0.35}=4.0\ \text{rad}=4.0\times\tfrac{180^\circ}{\pi}=229^\circ\approx2.3\times10^2$ degrees.
5 $60^\circ=\tfrac{\pi}{3}\ \text{rad}=1.047\ \text{rad}$; $2.5\ \text{rad}=2.5\times\tfrac{180^\circ}{\pi}=143^\circ$.
6 $\Omega=\tfrac{2.0\times10^{-4}\ \text{m}^2}{(0.50\ \text{m})^2}=8.0\times10^{-4}\ \text{sr}$; fraction $=\tfrac{8.0\times10^{-4}}{4\pi}=6.4\times10^{-5}$.
IV
Units in the real world.
  • 1 Medicine. A drug is infused at $2.5\ \text{µg}$ per kilogram of body mass per minute into a $60\ \text{kg}$ patient for one hour. How many milligrams are given?
  • 2 Sport. A marathon ($42.195\ \text{km}$) is run in $2\ \text{h}\ 1\ \text{min}\ 9\ \text{s}$. Find the runner's mean speed in m/s and km/h.
  • 3 Electronics. Light travels at $3.00\times10^8\ \text{m/s}$. How far does it go in one nanosecond? Why does this limit the size of a fast computer chip?
  • 4 Environment. $12\ \text{mm}$ of rain falls on a $1.5$-hectare field ($1\ \text{ha}=10^4\ \text{m}^2$). Find the volume of water in $\text{m}^3$ and in litres.
  • 5 Transport. A car uses $6.0\ \text{L}$ of fuel per $100\ \text{km}$. Show that this quantity has the unit of an area, express it in $\text{m}^2$, and interpret it.
1 $2.5\times60\times60=9000\ \text{µg}=9.0\ \text{mg}$. (A mix-up between µg and mg would give a thousandfold overdose.)
2 $t=7200+60+9=7269\ \text{s}$; $v=\tfrac{42\,195\ \text{m}}{7269\ \text{s}}=5.80\ \text{m/s}=20.9\ \text{km/h}$.
3 $3.00\times10^8\times10^{-9}=0.300\ \text{m}=30.0\ \text{cm}$. A signal cannot cross a large chip and return many times within one clock tick of a fraction of a nanosecond, so fast circuits must be small.
4 $V=0.012\ \text{m}\times1.5\times10^4\ \text{m}^2=1.8\times10^2\ \text{m}^3=1.8\times10^5\ \text{L}$ (about $1.8\times10^5\ \text{kg}$ of water).
5 $\tfrac{6.0\times10^{-3}\ \text{m}^3}{1.0\times10^5\ \text{m}}=6.0\times10^{-8}\ \text{m}^2$. Volume ÷ length = area: it is the cross-section of a "thread" of fuel as long as the journey, about $0.28\ \text{mm}$ across.
🎯 Exam corner BoardJEE MainJEE AdvancedNEET

E1. Board · 3 marks (a) Distinguish between a base unit and a derived unit, with one example of each. (b) Name the SI base quantities whose units are the kelvin and the candela. (c) Express the pascal in terms of SI base units.

(a) A base unit is the unit of one of the seven independent base quantities and is defined directly (e.g. the metre). A derived unit is built from base units through the defining equation of the quantity (e.g. the newton, $\text{kg m s}^{-2}$, from $F=ma$). [1]
(b) Kelvin: thermodynamic temperature. Candela: luminous intensity. [1]
(c) $1\ \text{Pa}=1\ \text{N/m}^2=\dfrac{\text{kg m s}^{-2}}{\text{m}^2}=1\ \text{kg m}^{-1}\text{s}^{-2}$. [1]
Exam tip In (c) show the intermediate step N/m²; examiners award the method mark for it.

E2. NEET Which of the following is not an SI base unit? (a) ampere (b) kelvin (c) newton (d) mole

Concept The seven base units are m, kg, s, A, K, mol, cd.
Answer (c) The newton is derived: $1\ \text{N}=1\ \text{kg m s}^{-2}$.
Exam tip Units named after people (newton, joule, watt, pascal) are almost all derived — the ampere and the kelvin are the two base-unit exceptions.

E3. JEE Main NEET Which pair of quantities has the same unit when written in SI base units? (a) work and power (b) pressure and energy per unit volume (c) momentum and force (d) impulse and power

Setup Reduce each to base units: work $\text{kg m}^2\text{s}^{-2}$, power $\text{kg m}^2\text{s}^{-3}$, momentum and impulse $\text{kg m s}^{-1}$, force $\text{kg m s}^{-2}$.
Key pair Energy per unit volume: $\dfrac{\text{J}}{\text{m}^3}=\dfrac{\text{N m}}{\text{m}^3}=\dfrac{\text{N}}{\text{m}^2}=\text{Pa}=\text{kg m}^{-1}\text{s}^{-2}$, the unit of pressure.
Answer (b).
Exam tip Momentum and impulse match each other, not force: impulse $=F\,\Delta t$ has an extra second.

E4. JEE Main (Numerical value) A $1.8\ \text{kW}$ hair-dryer is used for $10$ minutes every day for $30$ days. The energy used is $x\ \text{MJ}$. Find $x$.

SI first $P=1800\ \text{W}$, total time $t=30\times10\times60\ \text{s}=18\,000\ \text{s}$.
Energy $E=Pt=1800\times18\,000\ \text{J}=3.24\times10^7\ \text{J}=32.4\ \text{MJ}$.
Answer $x=32.4$ (equivalently $9.0\ \text{kWh}$).
Exam tip Check with kWh: $1.8\ \text{kW}\times5\ \text{h}=9\ \text{kWh}=9\times3.6=32.4\ \text{MJ}$. ✓

E5. JEE Advanced (One or more correct) Which of the following are equal to $1\ \text{kWh}$? (A) $3.6\ \text{MJ}$ (B) $3.6\times10^6\ \text{Pa m}^3$ (C) $3.6\times10^9\ \text{mJ}$ (D) $3.6\times10^6\ \text{kg m s}^{-2}$

Value $1\ \text{kWh}=3.6\times10^6\ \text{J}$.
(A), (C) $3.6\ \text{MJ}=3.6\times10^6\ \text{J}$ ✓; $3.6\times10^9\ \text{mJ}=3.6\times10^9\times10^{-3}\ \text{J}=3.6\times10^6\ \text{J}$ ✓.
(B) $\text{Pa m}^3=\text{N m}^{-2}\,\text{m}^3=\text{N m}=\text{J}$ ✓ — this is why $p\,\Delta V$ is a work.
(D) $\text{kg m s}^{-2}$ is the newton, a force, not an energy ✗.
Answer (A), (B), (C).
🔬 Research–Teaching NexusResearch-tutored · optional, about 30 minutes

Research question. How often do unit mix-ups cause medication errors in hospitals, and which unit conventions make them less likely?

Why it matters. Patient-safety agencies in many countries list confusion between mg and µg, between mL and mL/h, and between doses "per kg" and total doses among the commonest causes of serious drug errors. A factor of $1000$ hidden in a prefix can be fatal; this is exactly the conversion skill of this section.

What to do.

  1. A child of mass $18\ \text{kg}$ is prescribed $15\ \text{mg/kg}$ of paracetamol per dose. The syrup contains $120\ \text{mg}$ in $5.0\ \text{mL}$. Find the dose in mg and the volume in mL.
  2. An infusion must deliver $0.10\ \text{µg}$ per kg per minute to a $70\ \text{kg}$ adult. The bag holds $4.0\ \text{mg}$ in $250\ \text{mL}$. Find the pump rate in mL/h.
  3. Redo step 2 as if a nurse had misread µg as mg. By what factor is the rate wrong?
  4. Look up the guidance of a patient-safety body (for example the WHO or a national pharmacy council) on writing "µg" versus "mcg" and on trailing zeros such as "5.0 mg". Explain the reasons in terms of this section.

Tools: Calculator; a published patient-safety guideline.

Hand in: Your calculations with every unit written and cancelled, and a half-page summary of three rules you would put on a hospital poster.

Going further. Compare with the fuel mix-up at Gimli (1983) and the loss of NASA's Mars Climate Orbiter (1999). What do the three cases have in common?

Instructor note: step 1 — $270\ \text{mg}$, $11.25\ \text{mL}\approx11\ \text{mL}$; step 2 — $7.0\ \text{µg/min}=420\ \text{µg/h}=0.42\ \text{mg/h}$, concentration $0.016\ \text{mg/mL}$, rate $26.25\approx26\ \text{mL/h}$; step 3 — a factor of $1000$. Many guidelines advise writing "mcg" or "microgram" in handwriting because "µ" can be misread as "m", and never writing a trailing zero ("5.0 mg" misread as "50 mg").

🧪 Self-check quiz

0/5 correct

Q1. How many base units does the SI have?

Q2. The candela is the SI unit of

Q3. A speed of $72\ \text{km/h}$ equals

Q4. $1\ \text{µm}^2$ is equal to

Q5. Which is a correct way to write a speed of three metres per second?